Answer:
Error:
not 
Solution:x=0 and 3
Step-by-step explanation:
We have to find the error and correct answer
Given:![2ln x=ln(3x)-[ln9-2ln(3)]](https://tex.z-dn.net/?f=2ln%20x%3Dln%283x%29-%5Bln9-2ln%283%29%5D)
![lnx^2=ln(3x)-[ln9-ln3^2]](https://tex.z-dn.net/?f=lnx%5E2%3Dln%283x%29-%5Bln9-ln3%5E2%5D)
Using the formula

![lnx^2=ln(3x)-[ln9-ln9]](https://tex.z-dn.net/?f=lnx%5E2%3Dln%283x%29-%5Bln9-ln9%5D)





Therefore, x=0 and x=3
But last step in the given solution

It is wrong this property is used when
then

Hence, the student wrote
instead of
and solution is given by
x=0 and x=3
Answer:
should be 192
Step-by-step explanation:
Answer:
242 cm
Step-by-step explanation:
1. Find the scale factor
A scale factor (SF) is the ratio of two corresponding lengths in similar figures.
SF = actual distance/scale distance
If the scale width is 3.8 cm,
SF = 418 cm/3.8 cm = 110
2. Calculate the actual depth
110 = actual depth/2.2 cm
Actual depth = 110 × 2.2 cm = 242 cm
Dy/dx = (ycos(x))/(1 + y²)
(1 + y²)/y dy = cos(x) dx
(1/y + y) dy = cos(x) dx
Integrating:
ln(y) + y²/2 = sin(x) + c
ln(1) + 1/2 = sin(0) + c
c = 1/2
Thus,
ln(y) + y²/2 = sin(x) + 1/2