Since the big triangle is an isosceles one, we conclude that the angles of the left triangle are: 32, 90 and 3x-10. Sinche the sum of this angles have to be 180° we have:
Solving for x, we have:
Therefore, x=22.67 and the answer is A.
The area of a sector is 339.336 cm²
The area of a sector is defined to be as the region of space bounded by a boundary from the center of the circle.
It can be determined by using the formula:
Given that;
- Radius r = 18 cm
- Angle θ = 120°
Then. the area of the sector can be calculated as:
A = 339.336 cm²
Learn more about the area of a sector here:
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Hi lol I don’t understand you’re question I need more context
The interquartile range (IQR) is 15.
To find the IQR, you must:
1) Find the median
2) Split the data set in two at the median.
3) Find the medians from both the groups you made in Step 2
4) Label the smaller one Quartile 1 and the larger one Quartile 3 (Hint: The median is Quartile 2)
5) Subtract: Quartile 3 - Quartile 1