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Natali5045456 [20]
3 years ago
5

Help me plz I need help <3

Mathematics
2 answers:
inysia [295]3 years ago
7 0

24 will be the answer.

Charra [1.4K]3 years ago
3 0

Answer:

1st one twelve times the sum of a number plus twenty four

Step-by-step explanation:

12f=12xf(whatever number it is)

+

24        ^

twelve  l

times

the sum of a number + 24

You might be interested in
Assume that the ages for first marriages are normally distributed with a mean of 26 years and a standard deviation of 4 years. W
Snowcat [4.5K]

Answer:

0.7743

Step-by-step explanation:

Mean of age = u = 26 years

Standard Deviation = \sigma = 4 years

We need to find the probability that the person getting married is in his or her twenties. This means the age of the person should be between 20 and 30. So, we are to find P( 20 < x < 30), where represents the distribution of age.

Since the data is normally distributed we can use the z distribution to solve this problem. The formula to calculate the z score is:

z=\frac{x-u}{\sigma}

20 converted to z score will be:

z=\frac{20-26}{4}=-1.5

30 converted to z score will be:

z=\frac{30-26}{4}=1

So, now we have to find the probability that the z value lies between -1.5 and 1.

P( 20 < x < 30) = P( -1.5 < z < 1)

P( -1.5 < z < 1 ) = P(z < 1) - P(z<-1.5)

From the z-table:

P(z < 1) = 0.8413

P(z < -1.5) =0.067

So,

P( -1.5 < z < 1 ) = 0.8413 - 0.067 = 0.7743

Thus,

P( 20 < x < 30) = 0.7743

So, we can conclude that the probability that a person getting married for the first time is in his or her twenties is 0.7743

6 0
3 years ago
What is the quotient? −5 1/4 ÷2 3/4 Enter your answer as a mixed number, in simplified form, in the box.
ryzh [129]
The answer would be -1 10/11.

convert 5 1/4 to improper fraction

simplify 5 * 4 to 20

simplify 20 + 1 to 21

convert 2 3/4 to improper fraction

simplify 2 * 4 to 8

simplify 8 + 3 to 11

21/-4 * 4/11

21 * 4 over -4 * 11

84 over -4 * 11

84/-44

21/-11

convert to mixed fraction ( -1 10/11 )
4 0
3 years ago
I have a few questions! what is the gcf for
Harrizon [31]

Answer:

(21 and 54): 3

(55 and 90): 5

(16 and 30): 2

(42 and 91): 7

(66 and 121): 11

Step-by-step explanation:

5 0
3 years ago
tanji creates a "square, circle" repeating pattern. Kenji creates a "Square, circle, trianglr, cricle" repeating pattern. if bot
RoseWind [281]

Both tanji & kenji have same number of circles i.e. 50 .

<u>Step-by-step explanation:</u>

Here we have , tanji creates a "square, circle" repeating pattern. Kenji creates a "Square, circle, triangle, circle" repeating pattern. if both tanji and kenji have 100 shapes in their patterns,  . We need to find that which pattern contains more circles .Let's find out :

<u>tanji creates a "square, circle" </u>

it's given that tanji has 100 shapes and he is repeating this pattern . In this pattern circle comes 1 every time out of 2 shapes :

Total number of times circle = \frac{100}{2}(1)

Total number of times circle = 50

<u>Kenji creates a "Square, circle, triangle, circle" </u>

it's given that tanji has 100 shapes and he is repeating this pattern . In this pattern circle comes 2 every time out of 4 shapes :

Total number of times circle = \frac{100}{4}(2)

Total number of times circle = 50

Both tanji & kenji have same number of circles i.e. 50 .

3 0
3 years ago
I need this answer asappppp
Alex Ar [27]
Ill answer it for you 150 cubic meters
7 0
3 years ago
Read 2 more answers
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