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adell [148]
2 years ago
10

What are the coordinates of the roots of the equation x sqaured + 4x + 3= 0

Mathematics
1 answer:
scZoUnD [109]2 years ago
8 0

Answer:

a

x

2

+

b

x

+

c

=

0

the formula for the roots is

x

=

−

b

±

√

b

2

−

4

a

c

2

a

(

1

)

Identify the values for

a

,

b

,

&

c

x

2

+

4

x

+

3

=

0

cmp

a

x

2

+

b

x

+

c

=

0

a

=

1

b

=

4

c

=

3

(

2

)

Substitute these numbers into eh formula

x

=

−

4

±

√

4

2

−

(

4

×

1

×

3

)

2

×

1

(

3

)

Carefully proceed and do the calculations

x

=

−

4

±

√

16

−

12

2

x

=

−

4

±

√

4

2

x

=

−

4

±

2

2

now calculate the two separate solutions

x

1

=

−

4

+

2

2

=

−

2

2

=

−

1

x

2

=

−

4

−

2

2

=

−

6

2

=

−

3

Answer link

Step-by-step explanation:

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5 0
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blondinia [14]

\text{Consider the function}\\
\\
h(t)=\cot(t) \text{ on the interval }\left [ \frac{\pi}{4}, \ \frac{3\pi}{4} \right ]\\
\\
\text{we know that the average rate of change of a funtion f(x) over the }\\
\text{interval [a, b] is given by}\\
\\
f_{avg}=\frac{f(b)-f(a)}{b-a}\\
\\
\text{so using this, the average rate of change of the given function is}

h_{avg}=\frac{h\left ( \frac{3\pi}{4} \right )-h\left ( \frac{\pi}{4} \right )}{\frac{3\pi}{4}-\frac{\pi}{4}}\\
\\
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\\
=\frac{(-1)-(1)}{\frac{2\pi}{4}}\\
\\
=\frac{-2}{\frac{\pi}{2}}\\
\\
\text{Average rate of change of function}=\frac{-4}{\pi}

6 0
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