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3 years ago

6(2y - 1) - 2(2y) = 6

Mathematics

2 answers:

umka21 [38]3 years ago

7 0

The answer to this problem is y=3/2

Hatshy [7]3 years ago

3 0

Answer:

3/2

Step-by-step explanation:

replace dis in y to check your answer

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How do you calculate the volume for this shape

Bingel [31]

Answer:

The formula A=12bh is used to find the area of the top and bases triangular faces, A= area, b= base, and h= height. The formula A=lw is used to find the area of the three retangular side faces, A= area, l= lenght, and w= width

Step-by-step explanation:

3 0

3 years ago

PLEASEEE HELP USER THATS CORRECT GETS 50 POINTS AND BRAINLY CROWN Using the diagram, name two pairs of complementary and two pai

SVETLANKA909090 [29]

Answer:

Complementary: (2,3) & (1,9)

Supplementary: (6,7) & (5,8)

Step-by-step explanation:

8 0

2 years ago

Hey i rlly want to be done with thiss lol don't delete;-;

e-lub [12.9K]

Answer:

hello the correct answer is y=30x+20

Step-by-step explanation:

6 0

2 years ago

Solve each equation MUST SHOW WORK!!!! 10 points.

Sergio039 [100]

Answer:

1. x=34

2. c=8

3. x=9

4. m=32

That the answer for all 4.

Step-by-step explanation: Hope this help :D

4 0

3 years ago

Read 2 more answers

A hemisphere has an area of 256 pi cm^2. What is its volume?

Amanda [17]

$\bf \begin{array}{llll}
\textit{surface area of a sphere}\\\\
A=4\pi r^2
\\\\\\
\textit{a hemisphere is half that}\\\\
A=\cfrac{4\pi r^2}{2}\implies A=2\pi r^2
\end{array}\qquad r=radius
\\\\\\
\textit{now, we know the area is }256\pi \implies 256\pi =2\pi r^2
\\\\\\
\cfrac{256\pi }{2\pi }=r^2\implies \sqrt{128}=r\implies \boxed{8\sqrt{2}=r}
\\\\
-----------------------------\\\\$

$\bf \textit{volume of a sphere}\\\\
V=\cfrac{4}{3}\pi r^3\qquad r=radius
\\\\\\
\textit{a hemisphere is half that}\\\\
V=\cfrac{\frac{4}{3}\pi r^3}{2}\implies V=\cfrac{\frac{4\pi r^3}{3}}{\frac{2}{1}}\implies V=\cfrac{4\pi r^3}{3}\cdot \cfrac{1}{2}
\\\\\\
V=\cfrac{2\pi r^3}{3}
\\\\\\
\textit{now, we know the radius is }8\sqrt{2}\implies V=\cfrac{2\pi (8\sqrt{2})^3}{3}
\\\\\\
V=\cfrac{2\pi (8^3\sqrt{2^3})}{3}\implies V=\cfrac{2\pi \cdot 512\cdot 2\sqrt{2}}{3}
\\\\\\
\boxed{V=\cfrac{2048\pi \sqrt{2}}{3}}$

7 0

3 years ago