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VashaNatasha [74]
2 years ago
10

After cutting a piece 1.65 m long from a piece of cable, the remaining

Mathematics
1 answer:
Neko [114]2 years ago
3 0

Answer:

5.15 m

Step-by-step explanation:

To find how long the cable was originally, find the sum of the length of the piece that was cut off and the length of the remaining piece:

1.65 + 3.5 = 5.15

The cable was originally 5.15 m long.

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Which of the following is graphed Below
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Which has a greater slope, a horizontal line or a vertical line?
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3 years ago
An urn contains three red balls and four blue balls. Draw two balls at random from the urn, without replacement. Compute the exp
mezya [45]

Step-by-step explanation:

in total we have 3+4 = 7 balls.

when we draw the first ball, the probability to draw a red ball is 3/7, and a blue ball 4/7.

when we draw the second ball, we have now only 6 balls in total.

the probabilty to draw a red back now depends also on the result of the first draw.

if the first ball was already red, then we have only a chance now of 2 out of 6.

if the first ball was blue, then we have now a chance of 3 out of 6.

so, the probably to draw at least 1 red ball in 2 draws is the probability of drawing one on the first draw plus the probability of drawing one on the second :

1 - probability to see 2 blue balls

1 - 4/7 × 3/6 = 1 - 12/42 = 30/42 = 0.714285714...

the expected number of red balls in 2 draws is

1 red in first red in first red in second

but not second and second but not first

1×(3/7 × 4/6) + 2×(3/7 × 2/6) + 1×(4/7 × 3/6) = 12/42 + 12/42 + 12/42 = 36/42 = 6/7 = 0.857142857 ≈ 0.8571

7 0
2 years ago
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