Question

For the function ƒ, c is a constant and ƒ(3) = 12. What is the value of f(−3) ? ƒ(x) = cx2 + 30 A) −12 B) −2 C) 0 D) 12

Answer 1

Answer:

D. 12

Step-by-step explanation:

We have been given a function $f(x)=cx^{2}+30$, where c is a constant and f(3)= 12.

To find f(-3) we will find value of c by substituting value of f(3) in our given function.  

$12=c\times 3^{2}+30$    

$12=9c+30$  

$12-30=9c$

$9c=-18$

$c=\frac{-18}{9} =-2$

Upon substituting value of c in our given function we will get our function as $f(x)=-2x^{2}+30$

Now let us find f(-3) by substituting x=-3 in our function.

$f(-3)=-2(-3)^{2}+30$    

$f(-3)=-2(9)+30$

$f(-3)=-18+30$  

$f(-3)=12$

Therefore, f(-3) is 12 and option D is the correct choice.      

Answer 2

Answer:

The answer is D)12

Step-by-step explanation: