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Harman [31]
3 years ago
7

Solve the system algebraically. y = 3 - x 3x + 4y = 1 What is the value of x? -11 17/2 11

Mathematics
2 answers:
PtichkaEL [24]3 years ago
6 0
Y= 3 -x                         (1)

3x + 4y = 1                  (2)

Substitute (1) for y in (2)

3x + 4(3 - x) = 1

Expand, simplify and then solve for x

3x + 12 - 4x = 1
3x - 4x = 1 -12
-x = -11

x = 11

Aloiza [94]3 years ago
3 0

Answer:

The required value of x = 11

Step-by-step explanation:

The system of equations are given to be :

y = 3 - x .......(1)

3x + 4y = 1 ......(2)

We need to find the value of x by solving these two given system of equations

So, To solve the given equations : Putting value of y from equation (1) into equation (2)

⇒ 3x + 4y = 1

⇒ 3x + 4(3 - x) = 1

⇒ 3x + 12 - 4x = 1

⇒ -x = 1 - 12

⇒ -x = -11

⇒ x = 11

Thus, The required value of x = 11

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3 years ago
What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?
Pavel [41]

\boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}

<h2>Explanation:</h2>

Using the quadratic formula:

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \\ Here: \\ \\ f(x) = x^2 + 5x + 5 \\ \\ \\ So: \\ \\ a=1 \\ \\ b=5 \\ \\ c=5 \\ \\ \\ x=\frac{-5 \pm \sqrt{5^2-4(1)(5)}}{2(1)} \\ \\ x=\frac{-5 \pm \sqrt{25-20}}{2} \\ \\ x=\frac{-5 \pm \sqrt{5}}{2} \\ \\ \\ Two \ solutions: \\ \\ \boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}

<h2>Learn more:</h2>

Quadratic functions: brainly.com/question/12164750

#LearnWithBrainly

8 0
3 years ago
Please help me out!​
valina [46]

Answer:

4/11=.363636....

I hope this is good enough:

6 0
3 years ago
Will give brainliest! please answer correctly!
kompoz [17]
If I am not mistaking I think it is true sorry if it is wrong
5 0
3 years ago
Read 2 more answers
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