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3 years ago

Nine less than three times a number is greater than forty

1 answer:

7 0

Start with an equation.
Nine less... so -9
3 times a number = 3x
Greater than 40 is >40

So put together is 3x-9>40
When solving I imaging the greater than sign as an equal sign. Less confusing.
3x-9=40
3x=49
x>49/3

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Which is true about the degree of the sum and difference of the polynomials 3x5y – 2x3y4 – 7xy3 and –8x5y + 2x3y4 + xy3?

tankabanditka [31]

Answer:

The option " The sum has degree of 6 , but the difference has a degree of 7 " is correct.

Step-by-step explanation:

Given that the sum and difference of the polynomials $3x^5y-2x^3y^4-7xy^3$ and $-8x^5y+2x^3y^4+xy^3$

<h3>Now sum the given polynomials :</h3>

$3x^5y-2x^3y^4-7xy^3+(-8x^5y+2x^3y^4+xy^3)$

$=3x^5y-2x^3y^4-7xy^3-8x^5y+2x^3y^4+xy^3$

$=-5x^5y+0-6xy^3$

$=-5x^5y-6xy^3$

Therefore $3x^5y-2x^3y^4-7xy^3+(-8x^5y+2x^3y^4+xy^3)=-5x^5y-6xy^3$

In the simplified <u>sum of the polynomials</u> $-5x^5y-6xy^3$ we have <u>the degree is 6</u>

<h3>Now difference the polynomials </h3>

$3x^5y-2x^3y^4-7xy^3-(-8x^5y+2x^3y^4+xy^3)$

$=3x^5y-2x^3y^4-7xy^3+8x^5y-2x^3y^4-xy^3$

$=11x^5y-4x^3y^4-8xy^3$

Therefore $3x^5y-2x^3y^4-7xy^3-(-8x^5y+2x^3y^4+xy^3)=11x^5y-4x^3y^4-8xy^3$

In the simplified <u>difference of polynomials</u> $11x^5y-4x^3y^4-8xy^3$ we have <u>the degree is 7</u>

Therefore the option " The sum has degree of 6 , but the difference has a degree of 7 " is correct

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3 years ago

Read 2 more answers

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Arlecino [84]

I believe to find the range you just subtract the smallest from the largest:6.3-3.2=3.2

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irina [24]

Answer:

d= im not sure/ sorry

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mihalych1998 [28]

Fours=3
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$\\ \sf\longmapsto \dfrac{50}{110}\times 100$

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