1.49/6 = 0.248 rounds to 25 cents per oz
3.59 / 13 = 0.276 rounds to 28 cents per oz
choice A is the lowest rate
Answer:
d. None of the above.
Step-by-step explanation:
<em>a. By the law of large numbers, it would again be 46%.
</em>
FALSE. This proportion (46%) is a sample statistic, that can or can not be repeated in another sample.
<em>b. By the law of large numbers, the smaller (second) survey will certainly produce a sample proportion farther from the true population proportion than the larger (first) survey.
</em>
FALSE. Smaller samples will produce wider confidence intervals for the estimation of the population proportion, but larger samples does not necessarily gives us better point estimations of the true proportion. A small sample can be closer to the true proportion than a large sample, although is less probable.
<em>c. The proportion computed from the sample of 5000 people would be more accurate because smaller samples tend to be more homogeneous than larger samples.
</em>
FALSE. There is no evidence to claim that smaller samples are more homogeneous.
<em>d. None of the above.</em> TRUE
Answer:
The number of students we expect to have an interval that does not contain the true mean value is, ![255\times [\alpha\%]](https://tex.z-dn.net/?f=255%5Ctimes%20%5B%5Calpha%5C%25%5D)
.
Step-by-step explanation:
A [100(1 - α)%] confidence interval for true parameter implies that if 100 confidence intervals are created then [100(1 - α)] of these 100 confidence intervals will consist the true population parameter value.
Here α is the significance level. It is defined as the probability rejecting the claim that the true parameter value is not included in the 100(1 - α)% confidence interval.
It is provided that 255 students create the same confidence interval, correctly.
Then the number of students we expect to have an interval that does not contain the true mean value is,
For instance, if the students are creating a 95% confidence interval for mean then the number of students we expect to have an interval that does not contain the true mean will be:
The significance level is:
Number of students we expect to have an interval that does not contain the true mean will be: ![255\times [\alpha\%]=255\times 0.05=12.75\approx13](https://tex.z-dn.net/?f=255%5Ctimes%20%5B%5Calpha%5C%25%5D%3D255%5Ctimes%200.05%3D12.75%5Capprox13)
Thus, 13 of the 255 confidence intervals will not consist the true mean value.
Answer: The bench is $150 and the garden table is $300
Using the process of elimination, we will be able to determine the answer. So, 5x+3y=-10 multiply it by *3 to change the equation into 15x+9y=-30. Then to change 3x+5y=-6 multiply it by *5, to change it into 15x+25y=-30. So now with these two equations 15x+9y=-30 and 15x+25y=-30, use subtraction to get rid of the variable x.
Thus,
15x+9y=-30
-
15x+25y=-30
which will leave you with
-16y=0
thus, y=0
Then, plug y back into the original equation to find x
5x+3(0)=-10
5x=-10
x=-2
Thus the point of intersection is (-2,0)
-2 being the x, and y being 0.
