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Semenov [28]
3 years ago
15

What is the solution to 2x-8<12? x<2 x<8 x<10 x<40

Mathematics
1 answer:
maw [93]3 years ago
4 0
I believe the answer is x&it;10 if it’s incorrect i’m so sorry
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Circle O and triangle OQR are shown below. What is the length of OQ?
zysi [14]

Answer:

Step-by-step explanation:

A circle is inscribed in an equilateral triangle PQR with centre O. If angle OQR = 30°, what is the perimeter of the triangle?

This is a circle inscribed in an equilateral triangle with side s.

If you are asking for the perimeter of PQR, it is 3s.

If you are asking for the perimeter of OQR, it is (3+23–√3)s

Since OR and SR are the hypotenuses of right triangles with adjacent side equal to ½ s, their length is ½s / cos 30° = (√3) /3.

(3/3)s + ((√3) /3)s + ((√3) /3)s = ((3 + 2√3)/3)s ≈ 2.1547s

Hope it helps

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3 0
2 years ago
In circle p what is the measure of arc ab
S_A_V [24]
Remember the arc is equal to the central angle, so ab will equal angle APB. they told you angle APB is a right angle, how many degrees is this? that is what ab will be also:)
4 0
3 years ago
Help please area geometry !!
elena55 [62]

Answer:

37.5 cm^2

Step-by-step explanation:

The area of a parallelogram is

A = bh  where b is the base and h is the height

A = 7.5 * 5

A = 37.5 cm^2

4 0
3 years ago
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2nd question! BRAINLIEST and high points :D
Vesna [10]

Answer:

C

Step-by-step explanation:

One side is 60 so the other side is 60

X=20

4(20)-20=60

60=(4(20)-20)

60=80-20

60=60

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8 0
2 years ago
Find the length of diagonal XU in the hexagon below. Round your solution to 2 decimal points
SpyIntel [72]

Answer:

The length of diagonal XU is 6.40 units

Step-by-step explanation:

* Lets explain how to find the distance between two points

- The rule of the distance between two points (x_{1},y_{1})

 and (x_{2},y_{2}) is:

 d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

* Lets solve the problem

-From the attached figure:

- The coordinates of the vertex X are (2 , 2)

- The coordinates of the vertex U are (-2 , 7)

∴ The point (x_{1},y_{1}) = (2 , 2)

∴ The point (x_{2},y_{2}) = (-2 , 7)

∴ x_{1}=2,x_{2}=-2

∴  y_{1}=2,y_{2}=7

∵ d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

∴ d=\sqrt{(-2-2)^{2}+(7-2)^{2}}=\sqrt{(-4)^{2}+(5)^{2}}=\sqrt{16+25}=\sqrt{41}

∵ \sqrt{41}=6.403124

∴ d = 6.40

* The length of diagonal XU is 6.40 units

6 0
3 years ago
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