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padilas [110]
3 years ago
15

Find the sum of the infinite series 1/3 1/9 1/27 ...

Mathematics
1 answer:
Dmitry [639]3 years ago
6 0
Attached is the photo where I solved this problem.

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If a square has a side length of 5cm what would the area be
EastWind [94]

Answer:

25 cm squared

Step-by-step explanation:

To find area we multiply the side lengths

5cm x 5cm=25 cm squared

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3 years ago
Shana is forming kickball teams out of all of the students that signed up from two schools. Each team must have the same number
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Needs more info!!!!!!
6 0
2 years ago
Read 2 more answers
A) What is the domain and range of the graph? (Use the equations editor or explain)
riadik2000 [5.3K]

The domain: -5 < x ≤ 1 and the range: -3 ≤ y ≤ 1 is a function. b)

No, the vertical line crosses the graph in more than one place, therefore, the relation shown is a function.

<h3>What is the domain and range of the function?</h3>

The domain of a function is defined as the set of all the possible input values that are valid for the given function.

The range of a function is defined as the set of all the possible output values that are valid for the given function.

The domain of a relation is the set of values of the independent variable for a defined function.

The domain is the horizontal extent of the graph.

The range of a relation is the set of values of the dependent variable for a defined function.

The range is the vertical extent of the graph.

The vertical line can intersect the graph in at most one place.

a)

This graph extends from x > -5 to x = 1.

The domain

 -5 < x ≤ 1   ------   (-5, 1] in interval notation

This graph extends from y = -3 to y = 1.

The left side of the graph does not include the point (-5, 1), but the right side includes the point (1, 1).

y = 1 is one of the output values of the relation.

The range

 -3 ≤ y ≤ 1 . . . . . . . . [-3, 1] in interval notation

b)

No, the vertical line crosses the graph in more than one place, therefore, the relation shown is a function.

Learn more about the domain and range of the function:

brainly.com/question/2264373

#SPJ1

8 0
2 years ago
When calculating accrued interest over several years that compounds annually, you must _____.
Darina [25.2K]
When calculating accrued interest over several years that compounds annually, you must calculate a new principle each year, adding the accrued interest from the previous year. At the beginning of the new interest period, all the accrued interest is added to the principal which forms a new principle figure that the interest is then counted on. 
3 0
3 years ago
Ray UW is the angle bisector of Angle VUT. If the measure of Angle VUW = (4x + 6)° and the measure of Angle WUT = (6x – 10)°, wh
Lunna [17]

Hello! :)

Answer:

\huge\boxed{38^{\circ}}

--------------------------------------------------------------------------

An angle bisector divides an angle in half, therefore:

m∠VUW ≅ m∠WUT

Set the expressions equal to each other:

4x + 6 = 6x - 10

Subtract 4x from both sides:

6 = 2x - 10

Add 10 to both sides:

16 = 2x

Divide 2 from both sides:

x = 8.

Substitute in the value of "x" into the equation for ∠WUT:

6(8) - 10 = 48 - 10 = 38°.

3 0
3 years ago
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