Answer:
d = 115.4 mi
Step-by-step explanation:
Since it gives us the distance in between the locations, we simply label the distances:
From the Garbage to the Hotel is 58.3 miles.
From the Hotel to the Hardware Store is 57.1 miles.
We are trying to find the distance from the Garbage to the Hardware Store, we simply add the distances between:
58.3 mi + 57.1 mi = 115.4 mi
Find the mean without the outlier <br>
15, 34, 38, 42, 43, 36, 40, 35, 36, 38,
Temka [501]
Is real confusing with this outliers
It's evident that the first four terms are 4, 4/3, 4/9, and 4/27. So the fourth partial sum of the series is
![S_4=4+\dfrac43+\dfrac49+\dfrac4{27}](https://tex.z-dn.net/?f=S_4%3D4%2B%5Cdfrac43%2B%5Cdfrac49%2B%5Cdfrac4%7B27%7D)
It's as easy as adding up the fractions, but I bet this is supposed to be an exercise in taking advantage of the fact that the series is geometric and use the well-known formula for computing such a sum.
Multiply the sum by 1/3 and you have
![\dfrac13S_4=\dfrac43+\dfrac49+\dfrac4{27}+\dfrac4{81}](https://tex.z-dn.net/?f=%5Cdfrac13S_4%3D%5Cdfrac43%2B%5Cdfrac49%2B%5Cdfrac4%7B27%7D%2B%5Cdfrac4%7B81%7D)
Now subtracting this from
![S_4](https://tex.z-dn.net/?f=S_4)
gives
![S_4-\dfrac13S_4=4-\dfrac4{81}](https://tex.z-dn.net/?f=S_4-%5Cdfrac13S_4%3D4-%5Cdfrac4%7B81%7D)
That is, all the matching terms will cancel. Now solving for
![S_4](https://tex.z-dn.net/?f=S_4)
, you
have
![\dfrac23S_4=4\left(1-\dfrac1{81}\right)](https://tex.z-dn.net/?f=%5Cdfrac23S_4%3D4%5Cleft%281-%5Cdfrac1%7B81%7D%5Cright%29)
![S_4=6\left(1-\dfrac1{81}\right)](https://tex.z-dn.net/?f=S_4%3D6%5Cleft%281-%5Cdfrac1%7B81%7D%5Cright%29)
Answer:
One
Step-by-step explanation:
6z - 3z - 7 = -2 + 3
Combine like terms
3z-7 = 1
Add 7 to each side
3z-7+7 = 1+7
3z=8
Divide each side by 3
3z/3 = 8/3
z = 8/3
There is one solution
Answer:
5
m
^3
n^3
(
125
m^
4
+
2
m
−
6
)
Step-by-step explanation: