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3 years ago

????????????????????

1 answer:

3 0

It’s a diagram ur welcome

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Monica [59]

6*12=72 thus you can reduce the fraction to-

1/12

5 0

3 years ago

butalik [34]

To solve this question, we use the factor theorem, and using it, the polynomial function is:

$f(x) = x^3 - 2x^2 - 3x + 6$

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The factor theorem means that if k is a root of f(x), f(k) = 0.

Thus, applying the factor theorem for this question, we have to choose the function for which: $f(2) = 0, f(\sqrt{3}) = 0, f(-\sqrt{3}) = 0$

------------------------------

Function 1:

$f(x) = x^3 - 2x^2 - 3x + 6$

Testing the values:

$f(2) = 2^3 - 2(2)^2 - 3(2) + 6 = 8 - 8 - 6 + 6 = 0$

$f(\sqrt{3}) = \sqrt{3^3} - 2(\sqrt{3})^2 - 3\sqrt{3} + 6 = \sqrt{3^2\times3} - 6 - 3\sqrt{3} + 6 = 3\sqrt{3} - 3\sqrt{3} = 0$

$f(-\sqrt{3}) = -\sqrt{3^3} - 2(-\sqrt{3})^2 - 3(-\sqrt{3}) + 6 = -\sqrt{3^2\times3} - 6 + 3\sqrt{3} + 6 = -3\sqrt{3} + 3\sqrt{3} = 0$

Thus, since all three conditions are satisfied, $f(x) = x^3 - 2x^2 - 3x + 6$ is the polynomial function.

A similar question is given at brainly.com/question/11378552

5 0

2 years ago

Strike441 [17]

$560.673 is how much that nice chain would cost

7 0

2 years ago

son4ous [18]

5(x+y)= 20+ 3x
5x+5y=20+3x
5x+5y-3x=20+3x-3x
2x+5y=20
2x+5y-2x=20-2x
5y=-2x+20
5y/5=-2x/5+20/5
y=-2/5x+4

ANSWER: y=-2/5x+4

5 0

3 years ago

andrey2020 [161]

_
1.46<1.54 hope this helps

7 0

3 years ago