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Lynna [10]
4 years ago
13

First to answer will be the brainliest i need the answer ASAP

Mathematics
1 answer:
Iteru [2.4K]4 years ago
6 0

Answer:

<h2>x = -10</h2>

Step-by-step explanation:

-\dfrac{3}{4}(x+2)=6\qquad\text{multiply both sides by 4}\\\\4\!\!\!\!\diagup^1\cdot\left(-\dfrac{3}{4\!\!\!\!\diagup_1}\right)(x+2)=4\cdot6\\-3(x+2)=24\qquad\text{divide both sides by (-3)}\\\\\dfrac{-3\!\!\!\!\diagup^1(x+2)}{-3\!\!\!\!\diagup_1}=\dfrac{24}{-3}\\\\x+2=-8\qquad\text{subtract 2 from both sides}\\\\x+2-2=-8-2\\\\x=-10

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C=15 is the correct answer.
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3 years ago
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Hey can u please help i will give brainliy if u get it right :)
KATRIN_1 [288]

9514 1404 393

Answer:

  400 minutes

Step-by-step explanation:

The cost of the first plan is ...

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3 years ago
Convert 4 hours to minutes. There are 60 minutes in 1 hour.
FromTheMoon [43]

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8 0
4 years ago
Find the midpoint of the line segment joining the points P1 and P2<br>P1=(3,-4); P2=(5,4)
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To \ convert \ the \ standard \ form \ y = ax^2 + bx + c \ of \ a \ function \ into \ vertex \ form \\ \\ y = a(x - h)^2 + k ,\\ \\ we \ have \ to \ write \ the \ equation \ in \ the \ complete \ square \ form \ and \ vertex(h, k) \ is \ given \ by:

h = \frac{-b}{2a} , \ \ k = c -\frac{b^2}{4a} \\ \\y = a(x - h)^2+k

opens   up for a > 0, and  down for a < 0

y=x^2 +64x + 12\\ \\a=1,\ b=64 \ c = 12 \\ \\h = \frac{-64}{2}=-32 \\ \\ k = 12 -\frac{64^2}{4 }=12-\frac{4096}{4}=12-1024= -1012\\ \\y =  (x+32)^2-1012 \\ \\ This \ means \  the \  vertex \ of \ the \  parabola \ is \ at \ the \  point \ (-32, -1012)\\ \\ and \ the \  parabola \ is \ concave \ up.




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4 years ago
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