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I am Lyosha [343]
3 years ago
10

Please help me 3(x + 2) * 10 * 7 divided by 70 - 2 (x+2) Simplify

Mathematics
1 answer:
I am Lyosha [343]3 years ago
8 0

Answer:

= 105(x+2)/33-x

Step-by-step explanation:

Given the expression

[3(x+2)*10*7]÷70 - 2(x+2)

= 3(x+2)*70÷70 - 2(x+2)

= 210(x+2)/70-2x-4

= 210(x+2)/66-2x

= 210(x+2)/2(33-x)

= 105(x+2)/33-x

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Answer:

Step-by-step explanation:

To calculate percentages, start by writing the number you want to turn into a percentage over the total value so you end up with a fraction. Then, turn the fraction into a decimal by dividing the top number by the bottom number. Finally, multiply the decimal by 100 to find the percentage.

Hope this helps!

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3 years ago
8. What is the value of x?
xeze [42]

Answer:

I believe that x is equal to 10

Step-by-step explanation:

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2 years ago
In rectangle ABCD the diagonals intersect each other at point O and m∠ABD = 30°. Find BC if AC = 16 in
pashok25 [27]
16(sin 30degrees) = BC

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4 0
3 years ago
Read 2 more answers
Suppose a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 h
vladimir2022 [97]

A) The probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

B) The probability the golfer got exactly two holes-in-one during a single game is 8.57%.

C) The probability the golfer got six holes-in-one during a single game is close to 0%.

<h2 /><h2><u>How to determine probabilities</u></h2>

Since a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each, to determine A) what is the probability the golfer got zero or one hole -in-one during a single game, B) what is the probability the golfer got exactly two holes-in-one during a single game, and C) what is the probability the golfer got six holes-in-one during a single game , the following calculations must be performed:

  • 1 - 0.12 = 0.88
  • 0.88 ^ 17 = 0.1138
  • 0.88 ^ 18 = 0.1001

Therefore, the probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

  • 0.88 ^ 18 - 0.12 ^ 2 = X
  • 0.0857 = X

Therefore, the probability the golfer got exactly two holes-in-one during a single game is 8.57%.

  • 0.12 ^ 6 x 0.88 ^ 12 = X
  • 0.0000000001 = X

Therefore, the probability the golfer got six holes-in-one during a single game is close to 0%.

Learn more about probabilities in brainly.com/question/25273534

3 0
2 years ago
if the store purchased a kitchen appliance for $42 and sold it for $58.80, what was the percent markup?
oksano4ka [1.4K]

Answer:

40%

Step-by-step explanation:

Percent markup = new price - original price/original price

Do the subtraction first.

58.80 - 42.00 = 16.80

Now do the division

16.8/42 = 0.40

Change the decimal to a percent by moving the decimal two place to the right.

0.40 = 40%

6 0
2 years ago
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