Question

Omar is an avid video game player and movie watcher. He has a choice of belonging to a video club with a monthly fee of $12 and $1-a-day rental fee for any movie or game, or he can be a nonmemeber and pay $2.50-a-day rental fee for any movie or game. Find the number of movies or video games Omar must rent for one day for the cost to be equal between membership and nonmembership.

Answer 1

Answer:

8 movies or video games.

Step-by-step explanation:

Let x be the number of movies or video games on rent.  

We have been given that Omar has a choice of belonging to a video club with a monthly fee of $12 and $1-a-day rental fee for any movie or game. We can represent the charges for x movies or video games for a member of club as: $x+12$.

Omar can be a non-member and pay $2.50-a-day rental fee for any movie or game. We can represent the charges of a non-member for x movies or video games as: $2.5x$.

To find the number of movies for one day for the cost to be equal we will equate our both expressions.

$x+12=2.5x$

$x+12-x=2.5x-x$

$12=1.5x$

$x=\frac{12}{1.5}$

$x=8$

Therefore, Omar must rent 8 movies or video games for one day for the cost to be equal between membership and non-membership.

By renting 8 movies or video games charges for membership will be: 8+12=20.

By renting 8 movies or video games charges for a non-membership be: 2.5*8=20.

Hence charges of renting 8 movies or video games are same for both membership or non-membership.