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3 years ago

Plz help me with this

Mathematics

2 answers:

jekas [21]3 years ago

3 0

Answer:

10x^3 - 34x^2 + 33x - 7

Step-by-step explanation:

Multiply each term of the trinomial by each term of the binomial. Then combine like terms.

(2x^2 - 4x + 1)(5x - 7) =

= 10x^3 - 14x^2 - 20x^2 + 28x + 5x - 7

= 10x^3 - 34x^2 + 33x - 7

Y_Kistochka [10]3 years ago

3 0

Answer: 10x³ -34x² +33x - 7

Step-by-step explanation:

(2x² - 4x + 1)(5x - 7)

= (5x - 7)(2x² - 4x + 1)

= 5x(2x² - 4x + 1) -7(2x² - 4x + 1)

= 10x³ - 20x² + 5x

+ -14x² + 28x - 7

= 10x³ - 34x² + 33x - 7

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Given the sequence -3, 9, -27, 81, -243, ..., find the recursive formula.

Tanzania [10]

Answer:

$a_{n}$ = - 3 $a_{n-1}$

Step-by-step explanation:

There is a common ratio between consecutive terms of the sequence, that is

r = 9 ÷ - 3 = - 27 ÷ 9 = 81 ÷ - 27 = - 243 ÷ 81 = - 3

The recursive formula is of the form

$a_{n}$ = r $a_{n-1}$ = - 3 $a_{n-1}$

5 0

3 years ago

Mr. Jamison deposited $100 into a new savings account on January 1. On the first day of each month thereafter, he deposited thre

Lera25 [3.4K]

Answer:

$36 400

Step-by-step explanation:

Step 1

The first step is to figure out how much money is saved at the end of each month for the period from January 1 to June 15. The amount deposited at the end of each month is obtained by multiplying the amount from the previous month by 3.

The amount deposited in January is $\$100.$

The amount deposited in February is $1\$00\times 3= \$300.$

The amount deposited in March is $\$300\times 3= \$900.$

The amount deposited in April is $\$900\times 3= \$2\700.$

The amount deposited in May is $\$2\,700\times 3= \$8\,100.$

The amount deposited in June is $\$8\,100\times 3= \$24\,300.$

Step 2

The next step is to add up all the money that was deposited into the account. This calculation is shown below,

$\$100+\$300+900+\$\$2\,700+\$8\,100+\$24\,000=\$36\,400$

5 0

3 years ago

Read 2 more answers

The numbers of regular season wins for 10 football teams in a given season are given below. Determine the range, mean, variance,

tensa zangetsu [6.8K]

We have the following data set:

2,7,15,3,12,9,15,8,3,10

The range is the difference between the highest and lowest values in the set, to find the range, order the data set from least to greatest.

2,3,3,7,8,9,10,12,15,15

Then,

$\begin{gathered} \text{Range}=15-2 \\ \text{Range}=13 \end{gathered}$

Mean is represented by the following expression:

$\text{Mean}=\frac{\text{Sum of all data points}}{Number\text{ of data po}ints}$ $\text{Mean}=\frac{84}{10}=8.4$

Population variance formula looks like this:

$\begin{gathered} \sigma^2=\frac{\sum^{}_{}(x-\mu)^2}{N} \\ \text{where,} \\ \sigma^2=\text{population variance} \\ \sum ^{}_{}=addition\text{ of} \\ x=\text{each value} \\ \mu=population\text{ mean} \\ N=\text{ number of values in the population} \end{gathered}$

Then, substituting:

$\begin{gathered} \sigma^2=\frac{(2-14)^2+(3-14)^2+\cdots+(15-14)^2}{10} \\ \sigma^2=20.44 \end{gathered}$

For the standard deviation:

$\begin{gathered} s=\sqrt[]{\frac{\sum ^{}_{}(x-\mu)^2}{N}} \\ s=4.521 \end{gathered}$

5 0

1 year ago

Given the function h(x)=-4+6, Find the value of h(-2)

valina [46]

h(x) = -4 + 6

h(x) = 2

h(-2) = 2 because It's a constant function, when you substitute any x-values, you still get the same y-value.

Even if you substitute x = 1000, you still get y = 2.

Therefore, h(-2) = 2

-----------

If you mean h(x) = -4x+6

then h(-2) = 8+6 = 14

therefore, h(-2) = 14 for h(x) = -4x+6

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2 years ago

What is the value of the interquartile range of the data below? 6 12 14 24

Strike441 [17]

Answer:

Step-by-step explanation:

The interquartile range is the value of quartile 3 minus quartile 1.

The "box" part of this diagram has 3 lines, the left most, the middle, and the rightmost.

The leftmost line is Quartile 1. The right most is Quartile 3.

Hence

interquartile range = quartile 3 - quartile 1

Looking at the box plot, we can see that each small line in the number line is 2 units.

The leftmost line (quartile 1 ) is at 1 unit left of 30, so that is 30 -2 = 28

The rightmost line (quartile 3) is at 1 unit right of 40, so that is 40 + 2 = 42

Hence,

Interquartile range = 42 - 28 = 14

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3 years ago