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pashok25 [27]
3 years ago
11

To graph an inequality on a number line that is

Mathematics
1 answer:
Alborosie3 years ago
6 0

Answer:

open circle

Step-by-step explanation:

the answer is open circle

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There are 20 pens in a package. Ten of the pens are black, 8 are blue, and the rest are red.
azamat

Answer:

1:5 simplifies

Step-by-step explanation:

2 are red 10 are black. so it would be 2/10 or 2:10 (both means the same) however if you simplified it, it will be 1:5

3 0
3 years ago
One type of firework splits 5 times after it is fired into the air. The number of new bursts after each split can be modeled by
kherson [118]
Probably 5 because it only states 1 firework
5 0
3 years ago
Read 2 more answers
F(x) = 2x-(x+6) for f(-3)
ICE Princess25 [194]
Plug in -3 for x
f(-3) = 2(-3) - (-3 + 6)
f(-3) = -6 - (3)
f(-3) = -9
Solution: f(-3) = -9
4 0
2 years ago
Read 2 more answers
Help? please? anyone? thank youuu
Montano1993 [528]
The answer is 6. you just count the boxes in between the two points
8 0
3 years ago
Determine whether or not the vector field is conservative. if it is conservative, find a function f such that f = ∇f. (if the ve
Akimi4 [234]
A three-dimensional vector field is conservative if it is also irrotational, i.e. its curl is \mathbf 0. We have

\nabla\times\mathbf f(x,y,z)=-2e^{-x}\,\mathbf k

so this vector field is not conservative.

- - -

Another way of determining the same result: We want to find a scalar function f(x,y,z) such that its gradient is equal to the given vector field, \mathbf f(x,y,z):

\nabla f(x,y,z)=\mathbf f(x,y,z)

For this to happen, we need to satisfy

\begin{cases}f_x=ye^{-x}\\f_y=e^{-x}\\f_z=2z\end{cases}

From the first equation, integrating with respect to x yields

f_x=ye^{-x}\implies f(x,y,z)=-ye^{-x}+g(y,z)

Note that g *must* be a function of y,z only.

Now differentiate with respect to y and we have

f_y=-e^{-x}+g_y=e^{-x}\implies g_y=2e^{-x}\implies g(y,z)=2ye^{-x}+\cdots

but this contradicts the assumption that g(y,z) is independent of x. So, the scalar potential function does not exist, and therefore the vector field is not conservative.
8 0
3 years ago
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