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Nutka1998 [239]
3 years ago
11

What is -(3x - 12) = 9 x -4

Mathematics
1 answer:
OlgaM077 [116]3 years ago
3 0

Answer:

X = 1.3

Step-by-step explanation:

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Which expression correctly represents eight times the difference of 4 and a number
expeople1 [14]

Answer:

The expression for two times the difference of 4 and a number  is

8(4-d)

Step-by-step explanation:

To Find:

Write an expression for Eight times the difference of 4 and a number.

Solution:

Let the Unknown number be 'd'

Difference of 4 and d                        =      ( 4 - d )

So One Time Difference of 4 and d =  1× ( 4 - d )

∴   Two Times Difference of 4 and d = 2× ( 4 - d )

∴   Eight Times Difference of 4 and d = 8× ( 4 - d )

The expression for Eight times the difference of 4 and d. will be

8(4-d)

The expression for Eight times the difference of 4 and a number  is

8(4-d)

6 0
4 years ago
Based on the data provided, what is the expected cost of repairs over two years if each repair costs $60?
irina [24]
How many repairs a year?
6 0
4 years ago
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Can someone teach me how to do this type of thing?​
Aneli [31]

Answer:

it is 90*

Step-by-step explanation:

PLEASE BRAINLIEST!!!!!!!!

6 0
3 years ago
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Which of the following are equations for the line shown below? Check all that apply.
Nuetrik [128]

Answer: D. y+4=(x+2)

Step-by-step explanation: Once you subtract 4 from both sides, in order to solve for y (as the equation needs to be in the slope-intercept form, otherwise known as y=mx+b), you end up with y=x-2, which is the right answer. It is the correct answer because the y-intecept shown in the equation matches what is on the graph, in addition to the fact that the slope is just x.

4 0
3 years ago
An object is propelled upward from the top of a 300 foot building. The path that the object takes as it falls to the ground can
serg [7]

Answer:

As per the statement:

The path that the object takes as it falls to the ground can be modeled by:

h =-16t^2 + 80t + 300

where

h is the height of the objects and

t is the time (in seconds)

At t = 0 , h = 300 ft

When the objects hit the ground, h = 0

then;

-16t^2+80t+300=0

For a quadratic equation: ax^2+bx+c=0         ......[1]

the solution for the equation is given by:

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

On comparing the given equation with [1] we have;  

a = -16 ,b = 80 and c = 300

then;

t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}

t= \frac{-80\pm \sqrt{6400+19200}}{-32}

t= \frac{-80\pm \sqrt{25600}}{-32}  

Simplify:

t = -\frac{5}{2} = -2.5 sec and t = \frac{15}{2} = 7.5 sec

Time can't be in negative;

therefore, the time it took the object to hit the ground is 7.5 sec

8 0
4 years ago
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