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3 years ago

Which is an equivalent form of the equation 3x-3y=15

2 answers:

5 0

Simple....

change into y=mx+b form....

You have:

3x-3y=15

3x-3y=15
-3x -3x

-3y=15-3x

Divide by -3.....

$\frac{-3y}{-3} = \frac{15-3x}{-3}$

y=-5+x or y=x-5

Thus, your answer....A.

emmainna [20.7K]3 years ago

3 0

Hello ,
(3x-3y = 15) / 3
x-y = 5
so , it's A. y = x-5 .

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Q(x)= 1/2x - 3; q(x) =-4. Find the value of x

Lelu [443]

Answer:

$q(x) =-5$

Step-by-step explanation:

I am solving this using Function Notation.

We are given:

$q(x)= \frac{1}{2}x - 3$

While we are to find:

$q(x) =-4$

In Function Notation, replace all the " $x$ " you see with the value you are given.

So, in this case,

$q(x)= \frac{1}{2}x - 3\\\\=\frac{1}{2}x - 3$

Would become

$q(x)= \frac{1}{2}x - 3\\\\=\frac{1}{2}(-4) - 3$

Now we can solve.

$\frac{1}{2}(-4) - 3$

Use PEMDAS; Parenthesis first;

$\frac{1}{2}(-\frac{4}{1})$

Cross divide: 1 cancels 1, -4 ÷ 2 = -2

Hence, we are left with

$(-2) - 3$

$-5$

Therefore, the value of x is -5

8 0

2 years ago

9/16=27/x proportions?

tino4ka555 [31]

I think is
9 + x = 16 + 27
9 + x = 43
x = 52

3 0

3 years ago

You might need: What is the next term of the geometric sequence? -1/7, 4/7, -16/7<br>

Kryger [21]

A4= 64/7 a5=-256/7 a6=1024/7

5 0

2 years ago

Read 2 more answers

-4(2+8)=(-4xN)= Show your answers

Elanso [62]

Answer:

n=10

Step-by-step explanation:

$- 4(2 + 8) = ( - 4 \times n) \\ \frac{ - 4(10)}{ - 4} = \frac{ - 4n}{ - 4} \\ 10 = n$

5 0

2 years ago

Read 2 more answers

Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=

luda_lava [24]

Let $f(x) = x^3 - 2x - 2$ . Then differentiating, we get

$f'(x) = 3x^2 - 2$

We approximate $f(x)$ at $x_1=2$ with the tangent line,

$f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18$

The $x$ -intercept for this approximation will be our next approximation for the root,

$10x - 18 = 0 \implies x_2 = \dfrac95$

Repeat this process. Approximate $f(x)$ at $x_2 = \frac95$ .

$f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}$

Then

$\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}$

Once more. Approximate $f(x)$ at $x_3$ .

$f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}$

Then

$\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}$

Compare this to the actual root of $f(x)$ , which is approximately <u>1.76929</u>2354, matching up to the first 5 digits after the decimal place.

4 0

1 year ago