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kicyunya [14]
3 years ago
15

Based on the polynomial remainder theorem, what is the value of the function when x = 4? f(x)=x4−2x3+5x2−20x−4

Mathematics
2 answers:
Firdavs [7]3 years ago
4 0
The answer is f(x) = 124
const2013 [10]3 years ago
4 0
ANSWER

The remainder is

124

EXPLANATION

According to the remainder theorem, if

f(x) = {x}^{4} - 2 {x}^{3} + 5 {x}^{2} - 20x - 4

is divided by

(x - 4)

then the remainder is given by

f(4)

So we substitute
x = 4
into the given function to get,

f(4) = {4}^{4} - 2 {(4)}^{3} + 5 {(4)}^{2} - 20(4) - 4

We evaluate to get,

f(4) = 256- 2 {(64)} + 5 {(16)} - 20(4) - 4

This will simplify to,

f(4) = 256- 128 + 80- 80 - 4

f(4) = 124
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Hatshy [7]
Switch the x and y values and isolate y, then simplify.
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4 0
3 years ago
You operate a gaming Web site, www.mudbeast.net, where users must pay a small fee to log on. When you charged $3 the demand was
Doss [256]

Answer:

A) The linear relation between price and demand is:

d=-550x+2750

The revenue R is:

R=-550x^2+2750x

B) The profit functionP is:

P=-550x^2+2750x-30

C) The largest monthly profit is obtained with a log-on fee of $2.5 per month. This corresponds to a profit of $3407.5.

Step-by-step explanation:

We have a site where the number of log-ons depends on our monthly fee. A linear relation is established between the price (log-on fee) and the number of log-ons.

We have two points for this linear relationship:

  • At price x=3, the demand is d=1100.
  • At price x=2.5, the demand is d=1375.

We will model the relation:

d=mx+b

We can calculate the slope m as:

m=\dfrac{\Delta d}{\Delta x}=\dfrac{d_2-d_1}{x_2-x_1}=\dfrac{1375-1100}{2.5-3}\\\\\\m=\dfrac{275}{-0.5}=-550

Then, replacing one point in the linear equation, we can calculate the intercept b:

d_1=mx_1+b\\\\1100=(-550)\cdot 3+b\\\\1100=-1650+b\\\\b=1100+1650=2750

Then, the linear relation between demand and price is:

d=-550x+2750

The revenue R can be expressed as the multiplication of the price and the demand:

R=x\cdot d=x(-550x+2750)=-550x^2+2750x

If we have a fixed cost of $30 per month, the profit P is:

P=R-FC=-550x^2+2750x-30

We can maximize the profit by deriving the profit function and making it equal to zero.

\dfrac{dP}{dx}=0\\\\\\\dfrac{dP}{dx}=-550(2x)+2750(1)=0\\\\\\-1100x+2750=0\\\\x=\dfrac{2750}{1100}=2.5

This corresponds to a profit of:

P(2.5)=-550(2.5)^2+2750(2.5)-30\\\\P(2.5)=-550\cdot 6.25+6875-30\\\\P(2.5)=-3437.5+6875-30\\\\P(2.5)=3407.5

5 0
3 years ago
How many times would you expect to role a 2 on a 6 sided die in 50 trials
Keith_Richards [23]
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3 0
2 years ago
Two lines, A and B, are represented by equations given below: Line A: y = x − 2 Line B: y = 3x + 4 Which of the following shows
gavmur [86]

The solution to the system of equations is (-3, -5) because the point satisfies both equations

<h3>What is a linear function?</h3>

A linear function is in the form:

y = mx + b

Where m is the slope (rate of change) and b is the y intercept

Line A:

y = x − 2  (1)

Line B:

y = 3x + 4   (2)

Solving both equations simultaneously gives:

x = -3, y = -5

The solution to the system of equations is (-3, -5) because the point satisfies both equations

Find out more on linear function at: brainly.com/question/4025726

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Doss [256]
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5 0
3 years ago
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