<span>2x squared - 5
= 2(x)^2 - 5
= 2(4)^2 - 5
= 2(16) - 5
= 32 - 5
= 27</span>
There are 9 ways to get a spare
1 and 9
2 and 8
3 and 7
4 and 6
5 and 5
6 and 4
7 and 3
8 and 2
9 and 1
Answer:
y=3x+23 (lmk if you need me to explain)
Step-by-step explanation:
Here is not one equation that (6,24) is a solution for - there are many.
<span>y = 4 x is a simple one </span>
<span>y = -4 x + 48 is another</span>