Answer:
4 RW pink hair color
Explanation:
Let the allele for red hair color = R
Let the allele for white hair color = W
Let the allele for blue hair color = b
Since R and W exhibit co dominance it means none of both traits have the tendency or capability to masked the other .
As such individual with RW genotype = PInk hair color
Allele b is recessive and only individuals with the genotype bb exhibit the blue allele
Now; if a cross occurs between a red-haired Mendelian and a white-haired Mendelian
i.e
RR × WW
we have
R R
W RW RW
W RW RW
So we have the following offspring :
4 RW = 4 pink
So theoretically , the possible phenotypes results to 4 RW pink hair color
Anticoagulation therapy and elevation of the leg
I hope this helps
Answer:
D
Explanation:
Linoleic acid is an omega-6 fatty acid that is composed of an 18 carbon chain polymer. Most of the bonds are single bonds but few are double bonds. The double bonds form ‘kinks’ (bends) in the chains. The more the C=C bonds the more bendy the molecule. Nonetheless, it is significant to note that single (sigma) bonds are easy to rotate around their axis than double and triple (pi) bonds. The more the single bonds, the more flexibility the the molecule.
Answer:
0
Explanation:
This question involves two genes in Betta fish; one coding for body color and the other coding for tail colour. The allele for colored body (B) is dominant over the allele for white body (b) in the first gene while allele for blue tail (T) is dominant over allele for black tail (t) in the second gene.
Thus, in a cross between a Betafish that is homozygous dominant for both genes (BBTT) and homozygous recessive for both genes (bbtt), each parent will produce only one type of gamete combination
BBTT- BT
bbtt- bt
Using this in a punnet square, all offsprings will possess a genotype: BbTt.
Since alleles B and T are dominant, a Bettafish with genotype BbTt will be phenotypically color-bodied and blue-tailed.
Hence, according to the question, the probability of producing an offspring with white body and blue tails will be O since no offspring has such genotype.
