The table shown lists the atomic weight of the elements that begin with the letter c. What's the range of these

Bro pleas help me, that would be nice

algol13

Answer

i think the answer is c

sorry if wrong

Step-by-step explanation:

5 0

3 years ago

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Sue used to have a square garage with 286 ft squared of floor space. He recently built an addition to it. The garage is still a

nekit [7.7K]

Answer:

New Length = 20.71 feet

Original Length = 16.91 feet

22.47%

Step-by-step explanation:

Original area of the square garage = 286 ft squared

Addition of 50% more space

New area of the garage = 286 + .50(286)

= 286 + 143

= 429 square feet

What was the length of one side of the garage originally?

Original area of the square garage = 286 ft squared

Area of a square = length^2

286 = length^2

Find the square root of both sides

√286 = √length^2

Original Length = 16.91 feet

What is the length of one side of the garage now?

New area of the garage = 429 square feet

Area of a square = length^2

429 = length^2

Find the square root of both sides

√429 = √length^2

New Length = 20.71 feet

What was the percent increase in the length of one side?

(New length - old length) / old length × 100

= (20.71 feet - 16.91 feet) / 16.91 feet × 100

= 3.8 feet / 16.91 feet × 100

= 0.2247 × 100

= 22.47%

3 0

3 years ago

Wat is the slope of the line that passes through the points 3,1) and (-2,5)

den301095 [7]

Hi there!

»»————-　★　————-««

I believe your answer is:

$m=\boxed{-\frac{4}{5}}$

»»————-　★　————-««

Here’s why:

We can use the slope formula to find the slope of the two points given.

⸻⸻⸻⸻

$\boxed{\text{Recall that the slope formula is:}}\\\\\frac{y_2-y_1}{x_2-x_1}\\\\(x_1,y_1), (x_2,y_2)-\text{Points}$

⸻⸻⸻⸻

$\boxed{\text{Finding the Slope:}}\\\\\rightarrow m=\frac{5-1}{-2-3} \\\\\rightarrow m=\frac{4}{-5}\\\\\rightarrow \boxed{m= -\frac{4}{5}}$

⸻⸻⸻⸻

»»————-　★　————-««

Hope this helps you. I apologize if it’s incorrect.

8 0

3 years ago

Prove {0,2,0,2,0,2,...} does not converge

ElenaW [278]

Recall that a sequence $x_n$ is convergent if and only if $x_n$ is also a Cauchy sequence, which means to say that for any $\varepsilon>0$ , we can find a sufficiently large $N$ for which

$|x_m-x_n|$

whenever both $m$ and $n$ exceed $N$ .

But this never happens if we choose $m=n+1$ and $0$ ; under these conditions, we have

$|x_m-x_n|=|x_{n+1}-x_n|=2\not$

Therefore $x_n$ is not a Cauchy sequence and hence does not converge.

7 0

4 years ago

Can someone help me please???!!

Vlada [557]

Answer:

A

Step-by-step explanation:

When you shift down by 5 units, you are basically -5ing to every value in the bottom part of the chart.

For the bottom of the chart, I get:

0,2,8,14

While the top is

1,2,3,4 as nothing changes here.

The only chart like this is A.

4 0

4 years ago

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