Let they be x.
Cost of textbooks + laptops cant greater than total amount.
(cost of 1 textbooks * number of textbooks) + (cost of 1 laptop * number of laptops ≤ 6500
(30*116) + (x*439) ≤ 6500
3480 + 439x ≤ 6500
439x ≤ 3020
x ≤ 6.8(approx)
Last natural number is 6, says, they can buy 6 laptops at max.
Answer:
5 1/8 - 2 7/8 =
3 -6/8 =
2 2/8 =
2 1/4 =
2.25
Step-by-step explanation:
To answer this kind of question, you need to insert the first equation into second equation or vice versa. The equation from the question should be:
1. 3 paperback books + 5 hardcover book = $80.10
2. 7 paperback books + 4 hardcover book= $100.65
It would be easier to convert the 1st equation into
5 hardcover book = $80.10- 3 paperback books
hardcover book= $16.02- 0.6 paperback books
Then insert it to 2nd equation:
7 paperback books + 4 ($16.02- 0.6 paperback books)= $100.65
7 paperback books + $64.08- 2.4 paperback books= $100.65
4.6 paperback books = $100.65- $64.08= $36.57
paperback book= $7.95
Insert paperback book price to the first equation to find the hardcover book price
3 paperback books + 5 hardcover book = $80.10
3 ($7.95)+ 5 hardcover book = $80.10
5 hardcover book = $80.10 - $23.85= $56.25
hardcover book = $11.25
Then one paperback and one hardcoverbook= $7.95 + $11.25= $19.20
Let's use x as the number of questions she answered correctly. If we make an equation of out the question, it would be 8.7x+13=108.7 To solve the equation subtract 13 from both sides. So it will leave you with 8.7x=108.7-13, which is 8.7x=95.7. Divide both sides by 8.7, which will give you x=11. She answered 11 questions correctly.
Answer:
non of these answers are correct.