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1 year ago

6

Mary spent a total of $354.71 for a party. She spent $200.76 on food, plus an additional $30.79 for each hour of the party. How

long was the party?

1 answer:

Rainbow [258]1 year ago

7 0

Answer:

Total is 5 hours.

Step-by-step explanation:

... in the attached picture.

Hope this helps!

Choose me for brainliest please!!!

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Is line m: -x+2y=6 parallel, perpendicular, or neither parallel nor perpendicular to line n: y=-2x+6?

Serhud [2]

Make them both equal to y

y=-2x+6

2y=x+6 y=1/2x+3

These are perpendicular since ones slope is -2 and the other is the opposite, 1/2.

7 0

2 years ago

HELP PLEASE!!!!! IT DOESN'T EVEN SHOW UP ON GOOGLE!!!!!!!!!!!!!1

meriva

0.032 is the interest
since it is half a year, double this one
0.032 x 2 = 0.064

your formula is A = P(1 + (r/n)^nt
P is principle
R is rate
N is number of times
T is time

A = <span>32,675.12(1 + (0.032/2)^2(5)
A = 32675.12(1 + (0.016)^10
A = 32675.12(1.016)^10
A = 32675.12 (1.172)
A = 38295.24064
Your answer is ~38295.24

hope this helps

none of the answers make sense, because you can withdraw a lot more money from your bank account than that, unless you are missing some numbers and stuff</span>

5 0

2 years ago

Read 2 more answers

1. (a) Use the integral test to show that P[infinity] n=1 1/n4 converges. (b) Find the 10th partial sum, s10, of the series P[in

scZoUnD [109]

Answer:

Step-by-step explanation:

a) $\int\limits^{\infty} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}$

Substitute limits to get

= $\frac{1}{3}$

Thus converges.

b) 10th partial sum =

$\int\limits^{10} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}$

= $\frac{-1}{3} (0.001-1)\\= 0.333$

c) Z [infinity] n+1 1 /x ^4 dx ≤ s − sn ≤ Z [infinity] n 1 /x^ 4 dx, (1)

where s is the sum of P[infinity] n=1 1/n4 and sn is the nth partial sum of P[infinity] n=1 1/n4 .

(question is not clear)

3 0

3 years ago

A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square

kondaur [170]

This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

$V = xxy = x^{2}y$

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:

Surface area of the square base = $x^{2}$

Surface area of the rectangular sides = $4xy$

Therefore, the total area of the cube is:

$A = 48 ft^{2} = x^{2} + 4xy$

Isolating the variable y in terms of x:

$y = \frac{48- x^{2} }{4x}$

Substituting this value in V:

$V = x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}$

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

$\frac{dv}{dx} = 48-3x^{2} =0$

Solving for x:

$x = \sqrt{\frac{48}{3}} = \sqrt{16} = 4$

Solving for y:

$y = \frac{48- 4^{2} }{(4)(4)} = 2$

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ft
Width = 4 ft
Height = 2 ft

And its volume is:

$V = (4^{2} )(2) = 32 ft^{3}$

8 0

2 years ago

Let f of x equals the integral from x to 1 of the square root of the quantity of 1 plus t squared . use your calculator to find

ollegr [7]

Analytically, it will be

-√(1+1²) = -√2

The calculator shows it to be -1.41421356237

_____

= -√2 to 12 significant digits.

8 0

3 years ago