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3 years ago

What is the circumference of a rectangle when the length is 8 inches and the width is 4 inches

Mathematics

1 answer:

Nikolay [14]3 years ago

5 0

You multiply 8x4=32 and then divide 32÷2= 16in²

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The sale is being held from 11 a.m to 7 p.m on sunday, and from 9 a.m to 7 p.m on monday. How many hours will the sale last?

PSYCHO15rus [73]

8+10=18as your final answer

3 0

3 years ago

Read 2 more answers

The window is 60 inches wide. What is the width of the window in feet.

blsea [12.9K]

Answer:

5feet

Step-by-step explanation:

1 foot= 12 inches

1 inches = 1/12 feet

60 inches= 60x1/12= 5 feet

8 0

3 years ago

Which two equations are true?(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)=6.6×10−10 (6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.

tiny-mole [99]

let me edit your question as:

Which two equations are true?

Eq1:

(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)

Eq2:

6.6×10−10(6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.7×103)

Eq3:

2.7×103(7.5×106)−(2.5×106)=5×100

Answer:

No one is true

Step-by-step explanation:

let's check each equation, if the values on both sides (left and right side) are equal then the equation is true otherwise false.

Using PEMDAS rule we are simplifying the equations as;

Eq1:

$(2*10-4)+(1.5*10-4)=3.5*10-4(3*10-5)+(2.2*10-5)\\(16)+(11)=35-4(25)+(17)\\27=35-100+17\\27=-48\\$

Eq2:

$6.6*10-10(6.3*10-1)-(2.1*10-1)=3*10-1(5.4*103)-(2.7*103)\\66-10(62)-(20)=30-1(556.2)-278.1\\66-620-20=30-556.2-278.1\\-574=-804.1$

Eq3:

$2.7*103(7.5*106)-(2.5*106)=5*100\\221089.5-265=500\\220824.5=500\\$

we observed that none of the equation has two same values on both sides thus none of the three equations is true.

Also, no value of Eq1, Eq2 or Eq3 are same thus none of the equation is true

8 0

3 years ago

5c squared- d squared+3/2c - 4d...c= -1. d= -4

riadik2000 [5.3K]

For this case we have the following expression:

$5c ^ 2-d ^ 2 + \frac {3} {2} c-4d$

We must find the value of the expression when:

$c = -1\\d = -4$

Substituting we have:

$5 (-1) ^ 2 - (- 4) ^ 2 + \frac {3} {2} (- 1) -4 (-4) =\\5 (1) -16- \frac {3} {2} + 16 =\\5-16- \frac {3} {2} + 16 =\\-11- \frac {3} {2} + 16 =\\- \frac {25} {2} + 16 =\\\frac {-25 + 32} {2} =\\\frac {7} {2}$

Finally, the value of the expression is:

$\frac {7} {2}$

ANswer:

$\frac {7} {2}$

5 0

3 years ago

The royals softball team played 75 games and won 55 of them. What percent of the games did they lose (round to the nearest hundr

dimaraw [331]

If they won 55 of the games, that means they lost the rest of the 75. So,
75 - 55 = 20 games lost. To find the percentage of 20 out of 75, you set up a proportion:

$\frac{20}{75}=\frac{x}{100}$

where x = the percentage of games lost. Cross multiply and divide to isolate the x:

$\frac{20}{75}=\frac{x}{100}\\75x=2000\\75x/75=2000/75\\x=26.6666667$

Rounded to the nearest hundredth, the Royals lost 26.667 % of their games.

3 0

2 years ago

Read 2 more answers