I need help on this, anyone.
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The equation of the tangent line can be found using slope formula and fact that slope = dy/dx.
where (x0,y0) is point A ---> (0,-1)
Then rearrange equation into slope-intercept form:
Finally sub in x=0 into dy/dx to get slope at the point (0,-1)
where (x0,y0) is point A ---> (0,-1)
Then rearrange equation into slope-intercept form:
Finally sub in x=0 into dy/dx to get slope at the point (0,-1)