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matrenka [14]
3 years ago
10

The area of a regular octagon is 25 square cm . What is the area of a regular octagon with sides five times as large as the side

s of the first octagon?
Mathematics
1 answer:
Nutka1998 [239]3 years ago
3 0
When you change a dimension, it will change EACH dimension in the measurement you are finding.

Area is a two dimensional measurement, so you will need to multiply each dimension by 5, which is the same as multiplying the area by 25.

So, 25 square cm x 5 x 5= 625 square cm.

The area of the new OCTAGON is 625 square cm.
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Galina-37 [17]
Slope = (Y2-Y1) / (X2-X1)
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6 0
2 years ago
How many solutions does this equation have?
Greeley [361]

Answer:

No solution

Explanation:

-4+19-7f = -15-7

cancel terms on both sides ( add 7f on both sides)

Calculate the sum

-4+19= -15

-4+19=15

15 = -15

The statement 15 = -15 is false so there is no solution :)

4 0
2 years ago
When renting a limo for prom, the number of people varies inversely with the cost per person. Originally there were 4 people and
ioda

Answer:The new cost per person= $19 when there are 12 people

Step-by-step explanation:

Step 1

Let Number of people be rep as N

And Cost per person = C

such that the relationship of  number of people which varies inversely with the cost per person is given as

N∝ 1/C

Introducing constant of proportionality, k, we have that

N= K/C

such that when there were 4 people the cost per person was $57, K would be

N= K/C

4 = K /57

k= 57 X 4

k=228

Step 2

Therefore If the number of people changed to 12, cost per person would be

N= K/C

12= 228 / C

C= 228/12

C= 19

The new cost per person= $19 when there are 12 people

4 0
2 years ago
Which is larger 5/6 or 29/36
Whitepunk [10]

Answer: 5/6 > 29/36

<u>Find Common Denominator</u>

6: 6,12,18,24,30,36

36: 36,72,106

CD=36

<u>Multiply both sides by 6</u>

5/6×6/6=30/36

<u>Compare</u>

30/36 > 29/36

<u>Therefore</u>

5/6 > 29/36

6 0
2 years ago
Read 2 more answers
I need help I don't know how to do this​
Sidana [21]

Answer:

x\geq 23

Step-by-step explanation:

This equation can simply be solved by adding 15 to both sides.

To graph, draw a closed point at the center of the line and darken the area to the right of it.

5 0
2 years ago
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