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3 years ago

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The area of a regular octagon is 25 square cm . What is the area of a regular octagon with sides five times as large as the side

s of the first octagon?

1 answer:

Nutka1998 [239]3 years ago

3 0

When you change a dimension, it will change EACH dimension in the measurement you are finding.

Area is a two dimensional measurement, so you will need to multiply each dimension by 5, which is the same as multiplying the area by 25.

So, 25 square cm x 5 x 5= 625 square cm.

The area of the new OCTAGON is 625 square cm.

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How the heck do I do this? And what’s the answer?

stira [4]

Answer:

Option A

Step-by-step explanation:

We need to find two expressions that, when simplified, give the same results.

1) First, simplify the expression stated in the question. Multiply each of the terms in the parentheses by the number that is next to them. This would mean you have to multiply both 9x and -6 by $\frac{2}{3}$ . You also have to multiply $\frac{1}{2}x$ and $-\frac{1}{2}$ by 4. Then, simplify.

$\frac{2}{3}(9x-6) + 4 (\frac{1}{2} x - \frac{1}{2})\\\frac{18}{3}x- \frac{12}{3} + \frac{4}{2}x -\frac{4}{2} \\6x - 4 + 2x - 2$

2) Now, combine the like terms.

$6x - 4 + 2x - 2$

$8x - 6$

So, we need to find which of the expressions listed equal 8x - 6.

3) Let's try option A. Do the same as before. Multiply each of the terms in the parentheses by the number that is next to them. So, multiply 4x and -12 by $\frac{3}{4}$ . Also, multiply 30x and 18 by $\frac{1}{6}$ . Then, combine like terms and simplify.

$\frac{3}{4} (4x-12) + \frac{1}{6}(30x + 18)\\\frac{12}{4}x-\frac{36}{4} + \frac{30}{6} x + \frac{18}{6} \\3x - 9 + 5x + 3 \\8x - 6$

This also equals 8x - 6. Therefore, option A is the answer.

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2 years ago

How can numbers be expressed ordered and compared for a third grader

Anarel [89]

Line all the numbers in a column and compared where the numbers are not the same numbers

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4 years ago

You travel from point A to point B in a car moving at a constant speed of 70 km/h. Then you travel the same distance from point

tankabanditka [31]

Answer:

Yes, the average speed for the entire trip from A to C is equal to $80\frac{km}{h}$

Step-by-step explanation:

The average speed of an object is defined as the distance traveled divided by the time elapsed. Velocity is a vector quantity, and average velocity can be defined as the displacement divided by the time. For the special case of straight line motion in the x direction, the average velocity takes the form:

$V_a_v_e_r_a_g_e=\frac{x_2-x_1}{t_2-t_1}=\frac{Δx}{Δt}$

If the beginning and ending velocities for the motion are known, and the acceleration is constant, the average velocity can also be expressed as:

$V_a_v_e_r_a_g_e=\frac{V_1+V_2}{2}$

We Know that:

$V_1=70\frac{km}{h} \\\\V_2=90\frac{km}{h}$

Replacing the values:

$V_a_v_e_r_a_g_e=\frac{70+90}{2} =\frac{160}{2}=80\frac{km}{h}$

5 0

3 years ago

-6.2 - 12.6x = 5.8 - 7.8x

Sav [38]

Answer:

x = -2.5

Step-by-step explanation:

Step 1: Write equation

-6.2 - 12.6x = 5.8 - 7.8x

Step 2: Solve for <em>x</em>

<u>Add 12.6x on both sides:</u> -6.2 = 5.8 + 4.8x

<u>Subtract 5.8 on both sides:</u> -12 = 4.8x

<u>Divide both sides by 4.8:</u> x = -2.5

Step 3: Check

<em>Plug in x to verify if it's a solution.</em>

-6.2 - 12.6(-2.5) = 5.8 - 7.8(-2.5)

-6.2 + 31.5 = 5.8 + 19.5

25.3 = 25.3

7 0

3 years ago

A recent study at UGA (March 5, 2008) suggests that students with cell phones may take more risks than students that do not have

Ira Lisetskai [31]

Answer:

(a) -2.8

b) (1) Reject H0: p = 0.50 in favor of HA: p < 0.50; there is sufficient evidence to conclude that less than half of all UGA female students who, if they had a cell phone, would be willing to walk somewhere after dark that they would normally not go.

Step-by-step explanation:

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

H0: p = 0.50

This means that:

$\mu = 0.5, \sigma = \sqrt{0.5*0.5} = 0.5$

In a random sample of 305 UGA female students, 128 responded that, if they had a cell phone, they would be willing to walk somewhere after dark that they would normally not go.

This means that $n = 305, X = \frac{128}{305} = 0.4197$

a) Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.4197 - 0.5}{\frac{0.5}{\sqrt{305}}}$

$z = -2.8$

Pvalue:

We are testing the hypothesis that the proportion is less than 0.5, which means that the pvalue of the test is the pvalue of z = -2.81.

Looking at the z-table, z = -2.8 has a pvalue of 0.0026

(b) What is the correct conclusion for this hypothesis test at the 0.05 level of significance?

0.0026 < 0.05, which means that we reject the null hypothesis, that the proportion is 0.5, and accept the alternate hypothesis, that the proportion is less than 0.5, option (1).

6 0

3 years ago