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matrenka [14]
3 years ago
10

The area of a regular octagon is 25 square cm . What is the area of a regular octagon with sides five times as large as the side

s of the first octagon?
Mathematics
1 answer:
Nutka1998 [239]3 years ago
3 0
When you change a dimension, it will change EACH dimension in the measurement you are finding.

Area is a two dimensional measurement, so you will need to multiply each dimension by 5, which is the same as multiplying the area by 25.

So, 25 square cm x 5 x 5= 625 square cm.

The area of the new OCTAGON is 625 square cm.
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A sequence has an initial value (I) of -17 and its fourth term (a4) is 35. What is its general equation? Its 14th term?
aleksley [76]

Answer:

  1. The sequence is an Arthemtic Progression

An=A1+(n-1)d

A1 is first term, An is nth term, n is number of term, and d is common difference

therefore

A4=35, A1= -17

A4=A1+(4-1)d

35= -17+3d

35+17=3d

52=3d

52/3=3d/3

14=d

common diffrence(d)=14

  • The general solution is given by

An= -17+(n-1)14

An= -17+14n-14

An= -31+14n

<u>An= 14n-31</u>

A14 term, means n=14

From An=A1+(n-1)d

A14= -17+(14-1)14

= -17+(13×14)

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= 165.

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2. A sequence has a CR of 4/5 and its eighth term (a8) is (393216/3125). What is its general equation? Its 3rd term?

<u>solution</u>

common ratio(r)=4/5

eighth term(G8)=393216/3125

From Gn= G1r^(n-1)

G8 means n=8

G8=G1r^(n-1)

393216/3125=G1(4/5)^(8-1)

393216/3125=G1(4/5)^7

G1=(393216/3125)/(4/5)^7

G1=600

<u>The first term is given by G1=600</u>

  • Therefore

The General equation is given by

The General equation is given by Gn= 600(4/5)^(n-1)

3rd term (G3)

G3= G1(4/5)^(3-1) where n=3,

=600(4/5)^2

=600(16/25)

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C is the answer lil flock
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3x = 66
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Answer:

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Step-by-step explanation:

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