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3 years ago

What are 2 or more fractions of each of these??

Mathematics

2 answers:

Andrews [41]3 years ago

5 0

Answer:

Down below

Step-by-step explanation:

i. 80/100 = 4/5 = 80%

ii. 12.5/100 = 1/8

iii. 10/100 = 1/10

snow_tiger [21]3 years ago

4 0

I, 80/100 = 4/5
ii, 12.5/100 = 1/8
iii, 10/100 = 1/10

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Does 5 go into 100 equally

andreev551 [17]

Yes, 5 goes into 100 exactly 20 times because 5 multiplied by 20 is 100

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3 years ago

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S_A_V [24]

C= 5(9*3b)
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8 0

3 years ago

Simplify. (-5.12) - (-4.7) + (7.021) 6.79 6.601 -2.799

liq [111]

The answer is 6.601, and therefore, the second option.

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3 years ago

Read 2 more answers

Joe is building a post for his mailbox. To find the correct dimensions, he needs to expand this expression: (x-3) (x-9) (x-4) Se

kolbaska11 [484]

Answer:

$(x-3)(x-9)(x-4)=x^3-16x^2+75x-108$

Step-by-step explanation:

Given:

The expression to expand is given as:

$(x-3)(x-9)(x-4)$

Let us expand the first two binomials of the given expression using FOIL method.

The FOIL method states that:

$(a + b)(c + d) = ac + ad + bc + bd$

$(x-3)(x-9)=(x\times x)+(x\times -9)+(-3\times x)+(-3\times -9)\\\\(x-3)(x-9)=x^2-9x-3x+27=x^2-12x+27$

Now, let us multiply the result with the remaining binomial. Multiplying each term of the trinomial with each term of the binomial, we get:

$(x^2-12x+27)(x-4)\\\\= (x^2\times x)+ (x^2\times -4)+(-12x\times x)+(-12x\times -4)+(27\times x)+(27\times -4)\\\\=x^3-4x^2-12x^2+48x+27x-108\\\\=x^3-16x^2+75x-108...........(\because-12x^2-4x^2=-16x^2,48x+27x=75x)$

Therefore, the equivalent expression after expanding is given as:

$(x-3)(x-9)(x-4)=x^3-16x^2+75x-108$

3 0

3 years ago

The ratio of susan's money to isabella's money is 2:11. if susan $12, how much money does isbella have?

valentina_108 [34]

If Susan had 2$ and got to 12$ we need to find what multiplied by 2 = 12. So, 12/2=6
If 6x2=12 then 11x6=66
66$

7 0

3 years ago