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fomenos
3 years ago
12

2x - 5x = what does it equal Helppppp

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
6 0

Answer:

-3x hope this helps you good luck

Alexandra [31]3 years ago
4 0

Answer:

3x Thats the anser

Step-by-step explanation:

2x-5x=

2-5=3

add the x

3x

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Determine which ordered pair is a solution of y = –5x + 10. a. (–15, 5)
maria [59]
Y = - 5 x + 10
A ) x = - 15, y = 5
5 = 75 + 10
5 ≠ 85
B ) x = 2, y = 0
0 = - 5 · 2 + 10
0 = 0  ( correct )
C ) x = - 1,  y = - 5,
- 5 = 5 + 10
- 5 ≠ 15
D ) x = 3, y = 25
25 = - 15 + 10
25 ≠ - 5
Answer:
B ) ( 2, 0 )
7 0
3 years ago
Read 2 more answers
3/7 to 6/7. what is the percent of change
stepan [7]
Percent change = (new - old)/old * 100
(6/7 - 3/7)/(3/7) * 100
3/7 * 7/3 * 100
1 * 100
100%
4 0
3 years ago
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How do i do these fractions by 1/2?
Svetlanka [38]
I need to see the directions
4 0
3 years ago
In each diagram, abc is a straight line. Find the unknown angles.
aleksandr82 [10.1K]

Answer:

The value of ∠b = 180°

Step-by-step explanation:

Given that;

ABC is a straight line

Another angle is 137°

Find:

The value of ∠a

The value of ∠b

Computation:

We know that, ABC is a straight line

So,

137 + The value of ∠a = 180

The value of ∠a = 180 - 137

The value of ∠a = 43°

The value of ∠b = 360 - 137 - The value of ∠a

The value of ∠b = 360 - 137 - 43

The value of ∠b = 180°

6 0
3 years ago
Write a for loop that assigns summedvalue with the sum of all odd values from 1 to usernum. assume usernum is always greater tha
Lapatulllka [165]
// Input value is usernum.
// This code snippet sums 1 + 3 + 5 + ... + usernum
//  The answer is stored in the variable summedvalue.

N = (int) (usernum+1)/2;    // maximum number of integers to be summed
int *v = malloc(N*sizeof(int));     //  allocate storage for array v

// Calculate the number of loop counts and assign array v..
count = 0;
k = 1;
while (1) {
       if (k>usernum) {   //  do not extend v beyond usernum
          break;
          }
       v(count) = k;        //  assign an odd integer to v, including usenum
       count++;
       k += 2;                //  k is an odd number
       if k>usernum {          // handle usernum as odd or even
          k = usernum;
          } 
 }
n = count;          // the size of array v.

// Calculate the sum in a for loop
summedvalue  = 0;               // initialize summedvalue
for (i=0; i<=n; i++) {
     summedvalue += v(i);
    }


5 0
3 years ago
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