Ask question

Ask question

All categories

3 years ago

12

F=[

1 answer:

drek231 [11]3 years ago

5 0

Ummmm What?! Are you hacking or sum lol

You might be interested in

The sum of ten and the product of 4 and x

loris [4]

40 is the answer sorry if I’m wrong

8 0

3 years ago

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

<u>Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0</u>

Answer :

x = -4 or x = 2 ✅

Explanation :

<em><u>Quadratic</u></em><em><u> </u></em><em><u>formula </u></em><em><u>:</u></em><em><u> </u></em>ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions <em>(roots)</em> is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The <em><u>roots</u></em> of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) <u>Calculate </u><u>the </u><u>discrim</u><u>i</u><u>n</u><u>ant</u><u> </u><u>:</u>

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) <u>Calculate </u><u>the </u><u>roots </u><u>of </u><u>the </u><u>equation</u><u>:</u>

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$

>> Therefore, your answers are x = -4 or x = 2.

Learn more about <u>quadratic equations</u>:

brainly.com/question/27638369

6 0

2 years ago

Read 2 more answers

What are the relative frequencies, to the nearest hundredth, of the rows of the two-way table?

sveta [45]

Answer: A B

Group 1 0.25 0.75

Group 2 0.44 0.56

Step-by-step explanation:

Since we have given that

Number of people of A in group 1 = 15

Number of people of B in group 1 = 45

Total number of people in group 1 is given by

$15+45=60$

Relative frequency of people of A in Group 1 is given by

$\frac{15}{60}=0.25$

Relative frequency of people of B in Group 1 is given by

$\frac{45}{60}=0.75$

Similarly, Number of people of A in group 2 = 20

Number of people of B in group 2 = 25

Total number of people in group 2 is given by

$20+25=45$

Relative frequency of people of A in Group 2 is given by

$\frac{20}{45}=0.44$

Relative frequency of people of B in Group 2 is given by

$\frac{25}{45}=0.56$

Hence, A B

Group 1 0.25 0.75

Group 2 0.44 0.56

6 0

3 years ago

Find the length of AB when A(-4,1) and B(3,-1). Round to the nearest tenth (one decimal place) if necessary.

ivanzaharov [21]

Answer:

7.3 units is the answer rounded

8 0

3 years ago

Need help with this question.

Vaselesa [24]

Answer:

4:1 (I think)

Step-by-step explanation:

Let's write some equations first:

For both prices increasing by 20:

$\frac{x+20}{y+20} =\frac{5}{2}$

then we can use cross multiplication

2x+40=5y+100

For both prices decreasing by 5:

$\frac{x-5}{y-5} =\frac{5}{1}$

same here:

5y-25=x-5

Using substitution for 5y, we get: 5y=x+20

2x+40=5y+100

2x+40=x+20+100

x=80

plugging this in to the second equation:

5y-25=x-5

5y-25=80-5

5y-25=75

5y=100

y=20

therefore we get x:y=80:20

4:1

4 0

2 years ago