(1) R+G+B=50
(2) R=B+6
(3) G=B-4 so substitute G in (1)
R+B-4+B=50 substitute (2) in here
B+6+B-4+B=50 group like terms and solve
3B+2=50
3B=50-2
B=48/3=16 substitute in (2) and (3)
R=16+6=22
G=16-4=12
Check
22+12+16=50✅
Answer:
You have to invest $6,250
Step-by-step explanation:
very simple applying the simple interest formula which is

Given data
A, final amount
= $10,000
P, initial principal balance= ?
r, annual interest rate
= 7.5%
t, time (in years)= 8 years
we can substitute our given data to find the principal needed.

Divide both sides by 1.6 we have

P= $6,250
Answer:
he did half the diameter
Step-by-step explanation:
Answer:
D. The equations do not have the same solution because the second eqlition can never be obtained when multiplying the first
equation by any value
Step-by-step explanation:
-21=14 Equ(1)
6.1=-42 Equ(2)
Multiplying the first equation by -3 will give
-63= -42
Which is not equivalent to the second equation
Multiplying the first equation by 3, we have
-63=42
Not equivalent to the second equation
Multiplying both sides of the first equation by -4, we have
84=56
Not equivalent to the second equation
D. The equations do not have the same solution because the second eqlition can never be obtained when multiplying the first
equation by any value
Answer:
length = 60 foot, width = 30 foot
Step-by-step explanation:
Area of rectangular part, A = 1800 ft²
Cost of fencing three sides is $ 6 per foot and cost of one side fencing is $18 per foot.
Let the length of the rectangle is l and the width of the rectangle is W.
Area = Length x width
A = L x W
1800 = L x W ...... (1)
Total cost of fencing, C = 6 x ( L + W + L) + 18 x W
C = 6 (2L + W) + 18 W
C = 12 L + 24 W
Substitute the value of W from equation (1),
in equation (2)


Differentiate both sides with respect to L:

Put it equal to zero for maxima and minima

L = 60 foot
and W = 30 foot
So, the costing is minimum for length = 60 foot and the width = 30 foot.