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Mademuasel [1]
3 years ago
7

For each rotation, write the point or points that are the uppermost points of the rotated figure.

Mathematics
1 answer:
S_A_V [24]3 years ago
3 0
90 clockwise hope this helps
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The probability of waiting 4 minutes or longer for checkout at a particular supermarket counter is 0.1. On a given day, a man an
Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

Hope this photo will find you well

Good day!

3 0
3 years ago
Yeah. I need help with this
kiruha [24]

Answer:

:)

Step-by-step explanation:

well if you take 35x, which is 35 times whatever, + 70, you get y. so the first one is 35(1) + 70 = 105.

so i’ll go in order

35 x 1 + 70 = 105

35 x 2 + 70 = 140

35 x 3 + 70 = 175

35 x 4 + 70 = 210.

just multiply then add 70

hope this helped

7 0
3 years ago
Read 2 more answers
Please answer this!!
Reika [66]
The second one is correct
4 0
3 years ago
FIRST PERSON GETS BRAINLIEST
Sunny_sXe [5.5K]
X = 61 degrees.
Find the number of degrees in a pentagon by using the following formula:
(number of sides - 2)180 = 540.
There are 540 degrees in a pentagon.
Since we know four of the angles, we can subtract them from 540 to get the fifth angle.
540-138-144-107-90 = 61

Hope this helped =)
3 0
3 years ago
Read 2 more answers
5. If position of object x = 3 sinΘ – 7 cosΘ then motion of object is bounded between position.​
lesya692 [45]

9514 1404 393

Answer:

  ±√58 ≈ ±7.616

Step-by-step explanation:

The linear combination of sine and cosine functions will have an amplitude that is the root of the sum of the squares of the individual amplitudes.

  |x| = √(3² +7²) = √58

The motion is bounded between positions ±√58.

_____

Here's a way to get to the relation used above.

The sine of the sum of angles is given by ...

  sin(θ+c) = sin(θ)cos(c) +cos(θ)sin(c)

If this is multiplied by some amplitude A, then we have ...

  A·sin(θ+c) = A·sin(θ)cos(c) +A·cos(θ)sin(c)

Comparing this to the given expression, we find ...

  A·cos(c) = 3   and   A·sin(c) = -7

We know that sin²+cos² = 1, so the sum of the squares of these values is ...

  (A·cos(c))² +(A·sin(c))² = A²(cos(c)² +sin(c)²) = A²(1) = A²

That is, A² = (3)² +(-7)² = 9+49 = 58. This tells us the position function can be written as ...

  x = A·sin(θ +c) . . . . for some angle c

  x = (√58)sin(θ +c)

This has the bounds ±√58.

3 0
3 years ago
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