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3 years ago

Given: O is the midpoint of MN OM = OW Prove: OW = ON

Mathematics

2 answers:

xxMikexx [17]3 years ago

8 0

If O is the midpoint of NM that means that ON and OM are equal. And if OW=OM, then OW=OM=ON

mafiozo [28]3 years ago

3 0

Answer is in the attachment below.

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Whats the answer, can someone plz help me????

Greeley [361]

X/5 + 7 = 14

Subtract 7 from each side:

X/5 = 7

Multiply both sides by 5:

x = 7 * 5

X = 35

7 0

3 years ago

If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.

Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have $S_1=3\times2^{1-1}+2(-1)^1=3-2=1$ , which agrees with the initial value S₁ = 1.

• Assume the closed form is correct for all n up to n = k. In particular, we assume

$S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}$

and

$S_k=3\times2^{k-1}+2(-1)^k$

We want to then use this assumption to show the closed form is correct for n = k + 1, or

$S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}$

From the given recurrence, we know

$S_{k+1}=S_k+2S_{k-1}$

so that

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)$

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}$

$S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)$

$S_{k+1}=3\times2^k-2(-1)^k$

$S_{k+1}=3\times2^k+2(-1)(-1)^k$

$\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}$

which is what we needed. QED

6 0

2 years ago

In the following figure, JL is tangent to circle o at point K.

mixer [17]

Answer:

Step-by-step explanation:

the angle formed by radius and tangent are right angles

6 0

3 years ago

Estimate the sum by first rounding each

sukhopar [10]

5 3/8 rounds to 5,
4 7/10 rounds to 5
Your estimated sum is 10

5 0

3 years ago

Please help me with this pleaseee

torisob [31]

Answer:

x = 88.2

Step-by-step explanation:

The angle at the top of the triangle = 90° - 10° = 80°

and the left side of the triangle is x ( opposite sides of a rectangle )

Using the tangent ratio in the right triangle

tan80° = $\frac{opposite}{adjacent}$ = $\frac{500}{x}$

Multiply both sides by x

x × tan80° = 500 ( divide both sides by tan80° )

x = $\frac{500}{tan80}$ ≈ 88.2

5 0

3 years ago