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Artemon [7]
3 years ago
15

What is the solution?

Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
8 0

Answer:

A. {3+7i,3-7i}

Step-by-step explanation:

The given equation  is  x^2-6x+58=0

Use the quadratic formula with a=1,b=-6 and c=58

Recall the quadratic formula;

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

We substitute the given values to get;

x=\frac{--6\pm \sqrt{(-6)^2-4(1)(58)} }{2(1)}

x=\frac{6\pm \sqrt{36-232} }{2}

x=\frac{6\pm \sqrt{-196} }{2}

Recall that;

\sqrt{-1}=i

x=\frac{6\pm 14i}{2}

x=3\pm 7i

x=3+7i or x=3-7i

AysviL [449]3 years ago
4 0

Answer: OPTION A

Step-by-step explanation:

Apply the Quadratic formula, which is:

x=\frac{-b\±\sqrt{b^2-4ac}}{2a}

In this case:

a=1\\b=-6\\c=58

Then, you must susbtitute these values into the quadratic formula, as shown below:

x=\frac{-(-6)\±\sqrt{(-6)^2-4(1)(58)}}{2*1}

x=\frac{6\±\sqrt{-196}}{2}

Keep on mind that i=\sqrt{-1}, then you can rewrite it as following:

x=\frac{6\±14i}{2}\\\\\\x=\frac{2(3\±7i)}{2}\\\\x=3\±7i\\\\x_1=3+7i\\x_2=3-7i

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julia-pushkina [17]

Răspuns:

a) OC = 18cm

b) MN = 6cm

Explicație pas cu pas:

Găsiți diagrama la întrebarea atașată.

a) Din diagramă se poate observa că OC = OA + AB + AC

OC = 2n + 2n + 2 + 2n + 4

OC = 6n + 6

Următorul este să obțineți valoarea lui n:

OM = OA + AM

Să obținem segmentul AM;

Deoarece M este segmentul mijlociu al AC, atunci;

AM = AC / 2

AM = AB + BC / 2

AM = 2n + 2 + 2n + 4/2

AM = 4n + 6/2

AM = 2n + 3

Din moment ce OM = OA + AM

OM = 2n + 2n + 3

OM = 4n + 3

Dat fiind OM = 11

11 = 4n + 3

4n = 11-3

4n = 8

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Următorul pas este să calculați OC;

OC = 6n + 6

OC = 6 (2) + 6

OC = 18

Prin urmare, lungimea segmentului OC este de 18 cm

b) Această întrebare ne cere să găsim segmentul de linie MN.

Din diagramă, MN = AM - AN

Deoarece AM = 2n + 3 din întrebarea 1;

AM = 2 (2) +3

AM = 4 + 3

AM = 7

Acum, să obținem AN:

Din diagramă, AN = ON-OA și ON = OB / 2

AN = OB / 2 - OA

AN = (2n + 2n + 2) / 2 - 2n

AN = 4n + 2/2 - 2n

AN = 2n + 1 - 2n

AN = 2n-2n + 1

AN = 1

De la MN = AM - AN

MN = 7 - 1

MN = 6cm

Prin urmare, distanța dintre N, mijlocul segmentului OB și punctul M este de 6cm

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We have been given that the distribution of the number of daily requests is bell-shaped and has a mean of 38 and a standard deviation of 6. We are asked to find the approximate percentage of lightbulb replacement requests numbering between 38 and 56.

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z=\frac{x-\mu}{\sigma}

z=\frac{38-38}{6}=\frac{0}{6}=0

Now we will find z-score corresponding to 56.

z=\frac{56-38}{6}=\frac{18}{6}=3

We know that according to Empirical rule approximately 68% data lies with-in standard deviation of mean, approximately 95% data lies within 2 standard deviation of mean and approximately 99.7% data lies within 3 standard deviation of mean that is -3\sigma\text{ to }3\sigma.

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We know that mean is at center of normal distribution curve. So to find percentage of data points 3 SD above mean, we will divide 99.7% by 2.

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Step-by-step explanation:

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