Question

What is the solution?

Answer 1

Answer:

A. {$3+7i,3-7i$}

Step-by-step explanation:

The given equation  is  $x^2-6x+58=0$

Use the quadratic formula with a=1,b=-6 and c=58

Recall the quadratic formula;

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

We substitute the given values to get;

$x=\frac{--6\pm \sqrt{(-6)^2-4(1)(58)} }{2(1)}$

$x=\frac{6\pm \sqrt{36-232} }{2}$

$x=\frac{6\pm \sqrt{-196} }{2}$

Recall that;

$\sqrt{-1}=i$

$x=\frac{6\pm 14i}{2}$

$x=3\pm 7i$

$x=3+7i$ or $x=3-7i$

Answer 2

Answer: OPTION A

Step-by-step explanation:

Apply the Quadratic formula, which is:

$x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

In this case:

$a=1\\b=-6\\c=58$

Then, you must susbtitute these values into the quadratic formula, as shown below:

$x=\frac{-(-6)\±\sqrt{(-6)^2-4(1)(58)}}{2*1}$

$x=\frac{6\±\sqrt{-196}}{2}$

Keep on mind that $i=\sqrt{-1}$, then you can rewrite it as following:

$x=\frac{6\±14i}{2}\\\\\\x=\frac{2(3\±7i)}{2}\\\\x=3\±7i\\\\x_1=3+7i\\x_2=3-7i$