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irina [24]
3 years ago
11

Please help and show work

Mathematics
1 answer:
Zigmanuir [339]3 years ago
5 0

Answer:

1. 23

2. 8

Step-by-step explanation:

1. 180-157 = 23

2. 15²+x²=(9+x)²

225 +x²=81+18x +x²

225-81=18x

144 = 18x

x = 144/18 = 8

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Ruby conducted a survey and found the 5/6 of her classmates have a pet and 2/3 of those pets are dogs.what fraction of her class
Pie
To determine the fraction of her classmates with dogs as pets, we simply multiply the two given fractions based from the survey. 

                                       Pets = (2/3)(5/6) = 5/9

Thus, there are 5/9 of Ruby;s car. 
5 0
3 years ago
In a carnival drawing, a green ticket wins $1, a yellow ticket wins $5, and a blue ticket wins $10. There are 100 green tickets,
Evgesh-ka [11]

The odds in favor of winning $5 or more is 3 : 13

<h3>What are the odds in favor of winning $5 or more?</h3>

The odds of winning $5 or more can be determined by finding the ratio of the total value of tickets that have a value of $5 or greater to the total value of tickets.

Total number  of the tickets that have a value of $5 or more = 25 + 5 = 30

Total number of ticket  = 25 + 5 + 100 = 130

Ratio : 30 : 130

3 ; 13

To learn more about ratios, please check: brainly.com/question/9194979

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5 0
2 years ago
Find the midpoint of the line segment with end coordinates of:<br> (1,4) and (5,2)
poizon [28]
Midpoint formula: (x1+x2)/2, (y1+y2)/2
(1+5)/2 = 6/2 = 3 for x
(5+2)/2 = 7/2 = 3.5 for y
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8 0
3 years ago
Let x denote the courtship time for a randomly selected female–male pair of mating scorpion flies (time from the beginning of in
gavmur [86]

Complete Question:

a) Is it plausible that X is normally distributed?

b) For a random sample of 50 such pairs, what is the (approximate) probability that the sample mean courtship time is between 100 min and 125 min?

Answer:

a) It is plausible that X is normally distributed

b) probability that the sample mean courtship time is between 100 min and 125 min is 0.5269

Step-by-step explanation:

a)X denotes the courtship time for the scorpion flies which indicates that is a real - valued random variable, and since normal distribution is a continuous probability distribution for a real valued random variable, it is plausible that X is normally distributed.

b) Probability that the sample mean courtship time is between 100 min and 125 min

\mu = 120\\n = 50

P(x_{1}  < \bar{X} < x_{2} ) = P(z_{2}  < \frac{x_{2}- \mu }{SD} ) - P(z_{1}  < \frac{x_{2}- \mu }{SD})

SD = \sqrt{\frac{\sigma^{2} }{n} } \\SD = \sqrt{\frac{110^{2} }{50} } \\SD = 15.56

P(100 < \bar{X}

From the probability distribution table:

P(z_{2}  < 0.32 ) = 0.6255\\ P(z_{1}  < -1.29) = 0.0986

P(100 < \bar{X}

6 0
3 years ago
Which expressionis equal to (-7x+5.1y)-(-9x+5.3y)
Furkat [3]

Answer:

The simplified expression for the given expression will be:

c. 2x-0.2y

Step-by-step explanation:

Given expression:

(-7x+5.1y)-(-9x+5.3y)

To simplify the expression.

Solution:

In order to simplify the expression, we will first remove the parenthesis by reversing the signs of the terms inside the parenthesis which lies after a negative sign out side the parenthesis.

<em>This is because negative multiplies to a negative to give a positive and negative multiplies to a positive to give a negative.</em>

So, we have:

⇒ -7x+5.1y+9x-5.3y

Combining like terms

⇒ -7x+9x+5.1y-5.3y

<em>The like terms can be evaluated as</em>

-7x+9x=2x

5.1y-5.3y=-0.2y

Thus, the simplified expression will be:

⇒  2x-0.2y

7 0
3 years ago
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