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irina [24]
3 years ago
11

Please help and show work

Mathematics
1 answer:
Zigmanuir [339]3 years ago
5 0

Answer:

1. 23

2. 8

Step-by-step explanation:

1. 180-157 = 23

2. 15²+x²=(9+x)²

225 +x²=81+18x +x²

225-81=18x

144 = 18x

x = 144/18 = 8

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sergiy2304 [10]

Answer:

This would bring you to $160.00. This is because you initially had $20.00, because of the $13 and $7. Then, your family gave you a total of $140.00, and 140 + 20 = 160.

Step-by-step explanation:

3 0
3 years ago
Find the mean of the following data set. You may round to the
blagie [28]

Answer:

a . 2393.2

Step-by-step explanation:

7 0
3 years ago
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Dataset: 147; 159; 164; 182; 172; 171; 162; 163; 157; 145; 164; 188; 172; 163; 162; 164 and 166. a) Arrange the data into a stem
Molodets [167]

The mean of data is 164.70, median and mode of data are 164

Given that Dataset: 147; 159; 164; 182; 172; 171; 162; 163; 157; 145; 164; 188; 172; 163; 162; 164 and 166. and asked to arrange data in stem and leaf diagram and asked to determine mean, mode and median form the stem and leaf diagram

STEM                                    LEAF

14                                           5         7
15                                                       7    9
16                    2 2 3 3 4 4 4         6
17                  1 2 2
18                      2                                  8

Mean =\frac{total sum}{numberof terms}

Mean=\frac{2800}{17}

Mean= 164.70

Median⇒since there are 17 terms

Median= \frac{N+1}{2}the term

Median=9th term=164

Mode⇒ most frequent number

Mode⇒164

Therefore, 164 is mode and median ,164.70 is mean

Hence,The mean of data is 164.70, median and mode of data are 164

Learn more about mean here:

brainly.com/question/13451489

#SPJ9

3 0
2 years ago
A sinusoidal function whose period is 1/2 , maximum value is 10, and minimum value is −4 has a y-intercept of 3.
I am Lyosha [343]

Answer:

brainly.com/question/10395117

Step-by-step explanation:

5 0
4 years ago
(02.05 MC)
Amiraneli [1.4K]

Table for f(x)

\boxed{\begin{array}{c|c}\boxed{\bf x}&\boxed{\sf f(x)}\\ \sf 0 &\sf 1 \\ \sf 2&\sf 9\\ \sf 4 &\sf 17\end{array}}

Table for g(x)

\boxed{\begin{array}{c|c}\boxed{\bf x}&\boxed{\sf g(x)}\\ \sf 0 &\sf 1 \\ \sf 2&\sf 7\\ \sf 4 &\sf 13\end{array}}

Option C is correct

3 0
3 years ago
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