First of all, 4.7 * 2.9 = 13.63, so I think a mistake has occurred there and second, comma does not come here because this is not a big number, it is a small number. If you meant a dot instead. it would placed in the middle AKA 13.63
Would appreciate brainliest <3
(x^12)^5=x^(12*5)=x^60
(x^(-2))^9=x^(-18)
x^60*x^(-18)=x^(40) and we need to find x^a such that
x^(42)*x^a=x^(40)^5
x^a=x^(40)^5*x^(-42)
x^a=x^(200)x^(-42)
x^a=x^(200-42)
x^a=x^158
so the missing term is x^158
The easiest way to figure out probability problem with small data sets is to write out your entire sample space then divide by the total:
Sample size = 6 * 6 = 36
S = {[1,1],[1,2],[1,3],[1,4],[1,5],[1,6],[2,1],[2,2],[2,3],[2,4],[2,5],[2,6],[3,1],[3,2],[3,3],[3,4],[3,5],[3,6],[4,1],[4,2],[4,3],[4,4],[4,5],[4,6],[5,1],[5,2],[5,3],[5,4],[5,5],[5,6],[6,1],[6,2],[6,3],[6,4],[6,5],[6,6]}
The only way to make a number combination that's even while 1 die is odd is to have 2 odd numbers.
{[1,1],[1,3],[1,5],[3,1],[3,3],[3,5],[5,1],[5,3],[5,5]}
This gives us 9 results.
The probability of this happening is 9/36 = 1/4 = 0.25
Now if we have to get a 6 with the product being at most 15 we know that the biggest number that 6 can be multiplied by is 2 which gives us 12.
We are left with 4 options:
{[1,6],[2,6],[6,1],[6,2]}
The probability of this happening is 4/36 = 1/9 = 0.1111...
.8 is your answer. Because you can’t evenly divide ten into eight, you have to add a decimal then add a 0 behind the eight. 10 goes into 80 8 times evenly, so your answer is .8 (Sorry if it was confusing, but I hope the answer helps!)
