Question

A function g(x) has x-intercepts at (StartFraction 1 Over 2 EndFraction, 0) and (6, 0). Which could be g(x)? g(x) = 2(x + 1)(x + 6) g(x) = (x – 6)(2x – 1) g(x) = 2(x – 2)(x – 6) g(x) = (x + 6)(x + 2)

Answer 1

Answer:

$g(x) = (x-6)(2x-1)$

Step-by-step explanation:

$g(x)$ intercepts the x-axis at these 2 points:

$(6,0) ;(1/2,0)$

⇒ 6 and 1/2 are roots ie; if you insert $x=6$ or $x=1/2$ into the equation of g(x) you will obtain a 0.

$g(6) = g(1/2) = 0$

now in order for 0 to appear we should have $x-6$

now in order for 0 to appear we should have $x-1/2$

but  $x-1/2$ doesn't appear in any of these, but its multiple of 2 is there:

$2(x-1/2) = 2x-1$

Therefore the function;

$g(x) = (x-6)(2x-1)$

Answer 2

Answer:

its b

Step-by-step explanation:

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