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3 years ago

2. Brandon and his friends want to be at the amusement park by 1:30 pm. The bus

Mathematics

1 answer:

Ganezh [65]3 years ago

6 0

Answer:

11:30 am

Step-by-step explanation:

Since the bus travels at 50 mph and the park is 100 miles away, it will take 2 hours to get there. And since they want to be there by 1:30, they should leave two hours before, 11:30.

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Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below.

garik1379 [7]

Answer:

The 95% confidence interval would be given by $0.281 \leq \mu_1 -\mu_2 \leq 0.529$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_1 =9.2$ represent the sample mean 1

$\bar X_2 =8.8$ represent the sample mean 2

n1=27 represent the sample 1 size

n2=30 represent the sample 2 size

$\sigma_1 =0.3$ population standard deviation for sample 1

$\sigma_2 =0.1$ population standard deviation for sample 2

$\mu_1 -\mu_2$ parameter of interest.

Solution to the problem

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}}$ (1)

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =9.2-8.8=0.4$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $t_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$0.4-1.96\sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}=0.281$

$0.4+1.96\sqrt{\frac{6^2}{36}+\frac{7^}{49}}=0.519$

So on this case the 95% confidence interval would be given by $0.281 \leq \mu_1 -\mu_2 \leq 0.529$

6 0

3 years ago

If 60% of the students in your class like Burger King, how many students are in your class if 15 students like Burger King?

zloy xaker [14]

Answer:

Step-by-step explanation:

Let x be the number of students in the class

15 is 60% of x

60% of x can be written as 0.6x

15 = 0.6x

Divide by 0.6 on both sides

25 = x

There are 25 students in the class

Hope this helps :)

8 0

2 years ago

Enoch is two times as old as MARTIN.three years ago,the difference between their ages was fifteen years.find their present ages

olga2289 [7]

9514 1404 393

Answer:

Enoch is 30
Martin is 15

Step-by-step explanation:

The difference in ages remains the same over time. Enoch, at twice Martin's age, is still 15 years older. That means Martin is 15 and Enoch is 30.

5 0

3 years ago

the 41st term of the arithmetic sequence is -539 and the 54th term is -708. Find the value of the 80th term

yulyashka [42]

Answer:

$a _{n} = a _{1} + (n - 1)d \\ a _{41} = - 534 \\ a _{54} = - 708 \\ a _{41} = a _{1} + (41 - 1)d = - 534 \\ a _{1} + 40d = - 534 \: \: ...(1)\\ a _{54} = a _{1} + (54 - 1)d =- 708 \\ a _{1} + 53d = - 708 \: \: ...(2)$

Try to solve the similtanious equation to find the first term and the common difference, then use that information to figure out the 80th term... Update me if you need further help ...

7 0

3 years ago

Pls help this is a grade?!?!?!?

maksim [4K]

Net 2....................

5 0

3 years ago

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