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butalik [34]
3 years ago
9

Please help!!! 25 points! Which of these numbers are irrational?

Mathematics
1 answer:
Aleks04 [339]3 years ago
3 0

I belive that b is the answer.

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Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th
IgorLugansk [536]

Answer:

a) 0.32 = 32% probability that your bid will be accepted

b) 0.72 = 72% probability that your bid will be accepted

c) An amount in excess of $15,400.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

P(X \leq x) = \frac{x - a}{b-a}

Assume that the competitor's bid x is a random variable that is uniformly distributed between $10,400 and $15,400.

This means that a = 10400, b = 15400

a. Suppose you bid $12,000. What is the probability that your bid will be accepted (to 2 decimals)?

You will win if the competitor bids less than 12000. So

P(X \leq 12000) = \frac{12000 - 10400}{15400 - 10400} = 0.32

0.32 = 32% probability that your bid will be accepted

b. Suppose you bid $14,000. What is the probability that your bid will be accepted?

You will win if the competitor bids less than 14000. So

P(X \leq 14000) = \frac{14000 - 10400}{15400 - 10400} = 0.72

0.72 = 72% probability that your bid will be accepted

c. What amount should you bid to maximize the probability that you get the property (in dollars)?

His bid is uniformly distributed between $10,400 and $15,400.

So, to maximize the probability that you get the property, you should bid an amount in excess of $15,400.

6 0
3 years ago
A football team charges $30 per ticket and averages 20,000 people per game. Each person spend an average of $8 on concessions.Fo
olya-2409 [2.1K]

The ticket price that would maximize the total revenue would be $ 23.

Given that a football team charges $ 30 per ticket and averages 20,000 people per game, and each person spend an average of $ 8 on concessions, and for every drop of $ 1 in price, the attendance rises by 800 people, to determine what ticket price should the team charge to maximize total revenue, the following calculation must be performed:

  • 20,000 x 30 + 20,000 x 8 = 760,000
  • 24,000 x 25 + 24,000 x 8 = 792,000
  • 28,000 x 20 + 28,000 x 8 = 784,000
  • 26,000 x 22.5 + 26,000 x 8 = 793,000
  • 27,200 x 21 + 27,200 x 8 = 788,000
  • 26,400 x 22 + 26,400 x 8 = 792,000
  • 25,600 x 23 + 25,600 x 8 = 793,600
  • 24,800 x 24 + 24,600 x 8 = 792,000

Therefore, the ticket price that would maximize the total revenue would be $ 23.

Learn more in brainly.com/question/7271015

4 0
3 years ago
Please help asap !
quester [9]

Answer:

Step-by-step explanation:

4 0
3 years ago
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