Answer:
first option
Step-by-step explanation:
Given
f(x) = 
← factorise the numerator
= 
← cancel (x + 4) on numerator/ denominator
= 2x - 3
Cancelling (x + 4) creates a discontinuity ( a hole ) at x + 4 = 0, that is
x = - 4
Substitute x = - 4 into the simplified f(x) for y- coordinate
f(- 4) = 2(- 4) - 3 = - 8 - 3 = - 11
The discontinuity occurs at (- 4, - 11 )
To obtain the zero let f(x) = 0, that is
2x - 3 = 0 ⇒ 2x = 3 ⇒ x = 
There is a zero at ( , 0 )
Thus
discontinuity at (- 4, - 11 ), zero at ( , 0 )
(x-4)(x+1)
you’re welcome!
Correct Answer:
Option 3: <span>The quadratic function has two distinct real zeros.
The function is quadratic, therefore it can have only 2 zeros. The knowledge of x-intercepts is needed to determine the zeros, y-intercepts has nothing to do with the zeros of a function. The given function has 2 unique x-intercepts, so according to the fundamental theorem of algebra, this function has 2 distinct real roots as number of distinct real roots are equal to the number of x-intercepts. Therefore, option 3 is the correct answer. </span>
Answer:
4 11/40 hope this helps :)
Step-by-step explanation:
The answer is 12.69, you just need to put all the groceries together!!
