Hi,
the area of the square is … 6400
Answer:






Step-by-step explanation:
step 1
Find the value of x
we know that
----> by alternate interior angles
solve for x
Group terms


step 2
Find the measure of angle a
we know that
----> by vertical angles
substitute the value of x

step 3
Find the measure of angle b
we know that
----> by supplementary angles (form a linear pair)
we have

substitute


step 4
Find the measure of angle c
we know that
----> by vertical angles
we have

therefore

step 5
Find the measure of angle d
we know that
----> by corresponding angles
we have

therefore

step 6
Find the measure of angle e
we know that
----> by alternate exterior angles
we have

therefore

step 7
Find the measure of angle f
we know that
----> by vertical angles
we have

therefore

Answer:
x^8
Step-by-step explanation:
The applicable rule of exponents is ...
(x^a)(x^b) = x^(a+b)
Here you have ...
(x^3)(x^5) = x^(3+5) = x^8
X=21/2
X=10.5
X=10 1/2
There all right
Pls mark me brainliest
![\bf \stackrel{\textit{perimeter of a rectangle}}{P=2(L+w)}~~ \begin{cases} L=length\\ w=width\\ \cline{1-1} P=66 \end{cases}\implies 66=2(L+w) \\\\\\ 33=L+w\implies \boxed{33-w=L} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of a rectangle}}{A=Lw}\qquad \implies 216=Lw\implies 216=(33-w)w \\\\\\ 216=33w-w^2\implies w^2-33w+216=0 \\\\\\ (w-24)(w-9)=0\implies w= \begin{cases} 24\\ 9 \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bperimeter%20of%20a%20rectangle%7D%7D%7BP%3D2%28L%2Bw%29%7D~~%20%5Cbegin%7Bcases%7D%20L%3Dlength%5C%5C%20w%3Dwidth%5C%5C%20%5Ccline%7B1-1%7D%20P%3D66%20%5Cend%7Bcases%7D%5Cimplies%2066%3D2%28L%2Bw%29%20%5C%5C%5C%5C%5C%5C%2033%3DL%2Bw%5Cimplies%20%5Cboxed%7B33-w%3DL%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20a%20rectangle%7D%7D%7BA%3DLw%7D%5Cqquad%20%5Cimplies%20216%3DLw%5Cimplies%20216%3D%2833-w%29w%20%5C%5C%5C%5C%5C%5C%20216%3D33w-w%5E2%5Cimplies%20w%5E2-33w%2B216%3D0%20%5C%5C%5C%5C%5C%5C%20%28w-24%29%28w-9%29%3D0%5Cimplies%20w%3D%20%5Cbegin%7Bcases%7D%2024%5C%5C%209%20%5Cend%7Bcases%7D)
now, both values are valid, so if "w" is either one, "L" is the other.