Answer:
2/35
Step-by-step explanation:
There are 15 marbles in total.
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The answer would be .
What is the height of a rectangle whose base is 40 inches and whose diagonal is 41 inches?
2 answers:
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To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band
[recall 
or 20(x+5) if you wish.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band
The given function is
with
t = time, hours
f = temperature, °C
Because the maximum and minimum values for the Sine function are +1 and -1 respectively,
The maximum value of f = 33 - 20 = 13.
The minimum value of f = -33 - 20 = -53.
The period, T, is given by
Answer:
Maximum: 13°; Minimum: -53°; period: 4 hours
with
t = time, hours
f = temperature, °C
Because the maximum and minimum values for the Sine function are +1 and -1 respectively,
The maximum value of f = 33 - 20 = 13.
The minimum value of f = -33 - 20 = -53.
The period, T, is given by
Answer:
Maximum: 13°; Minimum: -53°; period: 4 hours