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Trava [24]
3 years ago
13

A code is formed using four of these letters: A, B, I, K, N, O, and T. (Note that the order of the letters in the code matters;

for example, ABIK is a different code from BAIK. )
The size of the sample space is 1.)_________
A.120 B.360 C.840 D.1680
. The probability that the first three letters of the four-letter code are vowels is 2.)_________.
A.1/35 B.1/60 C.1/140 D.101/105
Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
7 0
To answer this question, use permutation since the order of the letter matters. There are 7 letters and only 4 are to be used for the code. This  is a permutation of 7 taken 4 (7P4) which is equal to 840. Thus, the sample space is 840.
For the next questions, there are 3 vowels for as the first letter, only 6 letters are available for the second, 5 on the next, and 4 on the last. Multiplying these numbers give 360. To solve for probability, divide this number with the sample space. Thus, the answer is 3/7. 
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7 0
3 years ago
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Three merchants find a purse lying in the road. The first asserts that the discovery would make him twice as wealthy as the othe
Angelina_Jolie [31]

Answer: the system of equation would be :

  • A + Y = 2 (B+C)  
  • B + Y = 3B
  • C + Y = 5C

the three merchants would have 10 dollars, 10 dollars, and 5 dollars respectively

Step-by-step explanation:

before finding the purse, lets assume the wealth of the 3 merchants were as follows:

first merchant = A  dollars

second merchant = B dollars

third merchant = C dollars

  1. lets assume the purse contained Y dollars

After finding the purse they all claimed they would have the following:

first merchant said adding the money in the purse to his wealth would make him twice as rich as the other two combined : A + Y = 2 (B+C)  

second merchant said adding the money in the purse to his wealth would make his wealth triple  : B + Y = 3B

third merchant said adding the money in the purse to his wealth would make his wealth increase five folds : C + Y = 5C

third merchant = C dollars

therefore the system of equations to represent the problems are:

  • A + Y = 2 (B+C)  
  • B + Y = 3B
  • C + Y = 5C

2. now when the money in the purse is 20 dollars (Y= 20 dollars ), from the equations above

the second merchant will have :

B + Y = 3B  

 B + 20 = 3B

  3B - B = 20

  2B = 20

   B = 10 dollars

the third merchant will have :

C + Y = 5C

C + 20 = 5C

5C - C = 20

4C = 20

C = 5 dollars

the first merchant will have :

A + Y = 2 (B+C)  

A + 20 = 2 ( 10 + 5)

A = 2 (15) - 20

A = 30 - 20

A = 10 dollars

8 0
4 years ago
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anyanavicka [17]

Answer:

30/4

Step-by-step explanation:

7 times 4 = 28

28+2=30

7 0
3 years ago
keith made $306.00 for 18 hours of work at the same rate how many hours would he have to work to make $204.00
Mice21 [21]
306 / 18 = 17
So he's on $17 / hour

$204 / $17 = 12.
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4 0
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Determine whether the lines are parallel, intersect, or coincide.
Nana76 [90]

Answer:

The answer is intersect

Step-by-step explanation:

4 0
3 years ago
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