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Harman [31]
3 years ago
7

The numbers of calories burned, c, varies directly with the time spent exercising, t. When Lila bikes for 3 hours, she burns 900

calories.
Which equation shows direct linear variation for this situation?

c = 3t

c = 900t

c = 300t

c = t
Mathematics
1 answer:
vitfil [10]3 years ago
4 0
Umm not really sure but I'd go with A. You may need another source to double check my answer, I'm probably wrong.
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Here are 10 test scores: 30, 74, 76, 77, 78, 79, 80, 80, 82, 84. The mean of these scores is 74.
creativ13 [48]
We add up all those numbers (excluding 30) and divide by the number of numbers (9). This results in 78.8 (round up to 79).

79-74 = 5. So the mean has increased by 5 points. (C)
8 0
3 years ago
Find the difference (3-13x-7x^2)-(5x^2+ 12x-10)
Nikolay [14]
3 - 13x - 7x^2 - (5x^2 + 12x - 10)
Distributing the negative over the parentheses chamges the signs:-
= 3 - 13x - 7x^2 - 5x^2 - 12x + 10
adding like terms:-
= -12x^2 - 25x + 13  (answer).

Its B
8 0
3 years ago
Which expression has the greatest value?
anygoal [31]
Part 1:

A. = 8 • 10^20
B. = -8 • 10^20
C. = 4 • 10^25
D. = 6.25 • 10^23

A. has the greatest value


Part 2:

A. = 8 • 10^20
B. = -8 • 10^20
C. = 4 • 10^25
D. = 6.25 • 10^23

B. has the least value
7 0
3 years ago
A researcher is evaluating the influence of a treatment using a sample selected from a normally distributed population with a me
Bad White [126]

Answer:

The power of the test is 0.67.

Step-by-step explanation:

The complete question is:

A researcher is evaluating the influence of a treatment using a sample selected from a normally  distributed population with a mean of μ = 80 and a standard deviation σ = 20. The researcher  expects a 12-point treatment effect and plans to use a two-tailed hypothesis test with α = 0.05. Compute the power of the test if the researcher uses a sample of n = 16 individuals .

Solution:

The information provided are:

\mu=80\\\sigma = 20\\n = 16\\\alpha=0.05

The expected mean is:

\mu_{\bar x}=80+12=92

The critical <em>z</em>-score at <em>α</em> = 0.05 for a two-tailed test is:

<em>z</em> = 1.96

*Use a <em>z-</em>table.

Compute the test statistic value as follows:

z_{\bar x}=\frac{\mu_{\bar x}-\mu}{\sigma_{\bar x}}=\frac{92-80}{20/\sqrt{16}}=2.4

The power of statistical test is well-defined as the probability that we reject a false null hypothesis.

Power = Area to the right of the critical <em>z</em> under the assumption that H₀ is false.

Location of  critical <em>z</em> (in H₀ is false distribution) = z_{\bar x}-z

                                                                             = 2.4 - 1.96 \\= -0.44

This is negative because the critical z score is to the left of the mean  of the H₀ in false distribution.

Area above z = -0 .44.

Compute the value of P (Z > -0.44) as follows:

P(Z>-0.44)=1-P(Z

Thus, the power of the test is 0.67.

7 0
3 years ago
Please help with this question​
ioda

Answer:

25

Step-by-step explanation:

\frac{5^8 \times 5^{-2}}{5^4}

\frac{5^{8+-2}}{5^4}

\frac{5^{6}}{5^4}

5^{6-4}

5^2

=25

3 0
3 years ago
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