Question

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used

Answer 1

Answer:

Part 1) $2x^{2}-32=0----> (-4,4)$

Part 2) $4x^{2}-100=0----> (-5,5)$

Part 3) $x^{2}-55=9----> (-8,8)$

Part 4) $x^{2}-140=-19----> (-11,11)$

Part 5) $2x^{2}-18=0----> (-3,3)$

see the attached figure

Step-by-step explanation:

Solve each quadratic equation

Part 1) we have

$2x^{2}-32=0$

Adds 32 both sides

$2x^{2}=32$

Divide by 2 both sides

$x^{2}=16$

take square root both sides

$x=\pm4$

therefore

The solutions are (-4,4)

Part 2) we have

$4x^{2}-100=0$

Adds 100 both sides

$4x^{2}=100$

Divide by 4 both sides

$x^{2}=25$

take square root both sides

$x=\pm5$

therefore

The solutions are (-5,5)

Part 3) we have

$x^{2}-55=9$

Adds 55 both sides

$x^{2}=9+55$

$x^{2}=64$

take square root both sides

$x=\pm8$

therefore

The solutions are (-8,8)

Part 4) we have

$x^{2}-140=-19$

Adds 140 both sides

$x^{2}=-19+140$  

$x^{2}=121$

take square root both sides

$x=\pm11$

therefore

The solutions are (-11,11)  

Part 5) we have

$2x^{2}-18=0$

Adds 18 both sides

$2x^{2}=18$

Divide by 2 both sides

$x^{2}=9$

take square root both sides

$x=\pm3$

therefore

The solutions are (-3,3)