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kherson [118]
3 years ago
11

determine wheather the quadratic equation x square plus5xplus5 equal to zero have real roots and if so find the roots​

Mathematics
1 answer:
Oliga [24]3 years ago
5 0

Answer:

Step-by-step explanation:

Hello, please consider the following.

x^2+5x+5=0\\\\\Delta=b^2-4ac=25-20=5

The discriminant is positive so there are two distinct real solutions which are:

x_1=\boxed{\dfrac{-5-\sqrt{5}}{2}}\\\\x_1=\boxed{\dfrac{-5+\sqrt{5}}{2}}

Thank you

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Answer:

The √125 can be factored out to 25 and 5 then 25 can be factored out to 5 and 5. Then you pair up the numbers, you have a pair of 5's and a 5 left over. So the pair of 5's goes inside the radical as √5 and on the outside of the radical you have 5×3. So 3√125≈15√5.

Step-by-step explanation:

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The table represents some points on the graph of a linear function. What is the slope of the line?
8090 [49]

Answer:

-9/2!

Step-by-step explanation:

For this one, It's a bit hard! But, using the process of elimination, you can tell, that since the Y's are going down, this is a negative slope. Since there was only two answers, and only one was negative, it's -9/2!

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6 0
4 years ago
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Tcecarenko [31]

Answer:

27

Step-by-step explanation:

Remember to follow PEMDAS. Note that, when multiplying or dividing:

1) one positive and one negative = negative number

2) two positive = positive number

3) two negative = positive number

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Subtract:

35 - 8 = 27

27 is your answer.

~

8 0
3 years ago
Read 2 more answers
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