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vagabundo [1.1K]
3 years ago
13

Help please! This is due today and i totally forgot AHHHHH

Mathematics
1 answer:
Ghella [55]3 years ago
6 0
Where’s the picture?
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PLLLLLLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
LenaWriter [7]
The answer to this question is 23. How you get this is by adding all the sides like this: 2n+6+135+151+140+63=540. Then you just solve the equation.
8 0
3 years ago
Santiago is building a skateboarding ramp by propping the end of a piece of wood on a cinder block. If the ramp begins 63 centim
tensa zangetsu [6.8K]

Answer:

65 cm

Step-by-step explanation:

See the attached image.  The Pythagorean Theorem says in a right triangle, (leg)^2 + (leg)^2 = (hypotenuse)^2.

16^2+63^2=x^2\\256+3969=x^2\\4225=x^2\\x=\sqrt4225}\\x=65

3 0
3 years ago
Which of the following is equivalent to (5)^7/3
kifflom [539]
<em>The answer is \sqrt[3]{ 5^{7} }</em>

The reason we get this answer is because when you are converting from exponential form, to radical form you always place the numerator as our constant's exponent in the radical <em>( 5^{7} is called the radicand because it is located in the radical)</em> and the denominator in front of the radical, where it would be called the index. 

<em>Here's what a formula would look like:</em> ( \sqrt[n]{x} ) ^{q}=x^{ \frac{p}{q} }

Thank you for your question! I hope this helped! Have an amazing day and feel free to let me know if I can help you further! :D
3 0
2 years ago
Read 2 more answers
A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the
Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

             P.Q. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample average age = 25 years

            \sigma = population standard deviation = 1.8 years

            n = sample of students = 36

            \mu = population average age

So, 98% confidence interval for the average age, \mu is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.3263) = 0.98

P( -2.3263 \times {\frac{\sigma}{\sqrt{n} } < {\bar X - \mu} < 2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

P( \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } < \mu < \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

98% confidence interval for \mu = [ \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } , \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ]

                                                  = [ 25 - 2.3263 \times {\frac{1.8}{\sqrt{36} } , 25 + 2.3263 \times {\frac{1.8}{\sqrt{36} } ]

                                                  = [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0
3 years ago
This question has two parts. First, answer Part A. Then, answer Part B.
masya89 [10]

Answer:

$10.12

Step-by-step explanation:

Step one:

given data

we are told that the cost of binoculars is $155.75

and also the sales tax is 7%

Step two:

We want to first solve for the sales tax which is 7% of  $155.75

=7/100* 155.75

=0.070*155.75

=10.12

Cassie will pay a tax of $10.12

Also Cassie will pay a total amount of

= 155.75+10.12

=$165.87

3 0
2 years ago
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