It won't be enough, because in cause in total all they want to eat 35 but there's only 32
9514 1404 393
Answer:
3.6 s
Step-by-step explanation:
This is nicely solved by a graphing calculator. It takes about 3.6 seconds to hit the ground.
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We notice that the vertical velocity is a multiple of the leading coefficient, so we can solve this by completing the square.
0 = -4.9(t^2 -2t) +28 . . . . . for h = 0
28 +4.9 = 4.9(t^2 -2t +1) . . . . . rearrange, add 4.9 to both sides
32.9/4.9 = (t -1)^2
1 +(1/7)√329 = t ≈ 3.5912. . . . . square root and add 1
It takes about 3.6 seconds for the watermelon to hit the street.
Answer:
The coordinates of endpoint S are
.
Step-by-step explanation:
Let
and
, which is the midpoint of line segment ST. From Linear Algebra we get that midpoint is the following vector sum of endpoints S and T. That is:
(Eq. 1)
Now clear S in the previous expression:
(Eq. 1b)
Then, the coordinates of point S are:
![S(x,y) = 2\cdot (4,-6) - (0,6)](https://tex.z-dn.net/?f=S%28x%2Cy%29%20%3D%202%5Ccdot%20%284%2C-6%29%20-%20%280%2C6%29)
![S(x,y) = (8, -18)](https://tex.z-dn.net/?f=S%28x%2Cy%29%20%3D%20%288%2C%20-18%29)
The coordinates of endpoint S are
.