sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250
<u>Step-by-step explanation:</u>
We need to find sum of sequence : 46 + 42 + 38 + ... + (-446) + (-450)
Given sequence is an AP with following parameters as :

So , Let's calculate how many terms are there as :
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Sum of an AP is :
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250
13. 81.64
14. 803.84
15. 153.83
16. 753.6
you just use circumference and area formulas for a circle
123a
123q
123w
123e
123r
123t
123y
123u
123i
123o
123p
123s
123d
123f
123g
123h
123j
123k
I thought this would be easy lol, I tried, sorry for not getting an answer
Un grouping in 3rd grade maths can also be called subtracting