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3 years ago

Help please i will give brainlist

Mathematics

1 answer:

Feliz [49]3 years ago

5 0

Answer:

Angle 1 is 67 and Angle 2 is 46

Step-by-step explanation:

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Express 14.63 as a mixed number

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14 will be your whole number and your fraction would be 63/100, so the entire thing as a mixed number is 14 63/100

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3 years ago

Y = -5/3x + 3 <br> y= 1/3x - 3<br><br> And graphing it

tigry1 [53]

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−

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2 years ago

How far is Mars from the sun actually formatted

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3 years ago

A tent with a price of $165 is subject to a sales tax of 5%. What is the total price of the tent?

Svetllana [295]

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3 years ago

at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t

baherus [9]

The probability that a student participates in both sports and drama is $0.14$ .

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If $A$ and $B$ are any two events, then the probability of the joint event $(A\cup B)$ is given by the following formula: $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose $S$ denotes that "a student participates in sports" and $D$ denotes that "a student participates in drama".
So, we have $P(S)=\frac{42}{100}=0.42$ , $P(D)=\frac{25}{100}=0.25$ , $P(S\cup D)=\frac{53}{100}=0.53$ .

We want to find the probability that a student participates in both sports and drama i.e., we want to find $P(S\cap D)$ .

By the above formula, we obtain:

$P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}$

Therefore, the probability that a student participates in both sports and drama is $0.14$ .

To learn more about probability, refer: brainly.com/question/24756209

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6 0

1 year ago

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